to a depth of 100mm and rest with air. What is the pressure at the bottom of the periphery of the tank? 200 0.10 AIR 0.20
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- Q3. Water flows through pipes A and B. Lubricating oil is in the upper portion of the inverted U, Mercury is in the bottom of the manometer bends. Determine the pressure difference, pA-pB in units of kPa. B Oil 0:25 m 25 cm H,0-10 cA H,0 20 cA 507 13 cn 15 Rotm4.) A 75 mm diameter pipe, 2 m long is just filled with oil (sp. gr. = 0.822) and then capped, and place on horizontal position. It is rotated at 27.5 rad/sec about a vertical axis 0.5 m from one end (outside the pipe). What is the pressure in kPa at the far end of the pipe? Answer: 1865 Kpa Subject: Fluid Mechanic Lesson: Relative Equilibrium of Liquids Fundamentals of Fluid FlowA pipe carrying oil of sp gr 0 877 changes in A pipe carrying oil of sp gr 0.877 changes in size from 150mm at section E to 450mm at section R Section E is 3 66m lower than R section R. Section E is 3.66m lower than R and the pressures are 91.0kPa and 60.3kPa, respectively. If the discharge is 0.146m3 respectively. If the discharge is 0.146m /s, determine the lost head and the direction of flow.
- 13. A U-tube differential manometer connects two pressure pipes A and B. Pipe A contains carb tetrachloride having a specific gravity 1.594 under a pressure of 11.772 N/cm2 and pipe B contains oil of sp. gr. 0.8 under a pressure of 11.772 N/em. The pipe A lies 2.5 m above pipe B. Find the difference of pressure measured by mercury as fluid filling U-tube. 14. A differential manometer is connected at the two points A and B as shown in Fig. 2.25. At B air pressu is 7.848 N/cm² (abs.), find the absolute pressure at A. [Ans. 31.36 cm of mercury] [Ans, 6.91 N/em) AIR B WATER OIL Sp. gr.0.8 OIL Sp. gr. 0.8 50'cm 30 cm om 100 cm 50 cm 10 cm MERCURY Sp. gr. 13.6 WATER Fig. 2.25 Fig. 2.26A pressure gage at elevation of 12m at the side of the tank containing liquid reads 100 kPa. Another gage at elevation 7 m reads 140 kPa. Compute the specific weight of the liquid. 100 kPa - El. 12 Sm 140 kPa El. 7FRESHMEN What is the value of F required to balance the weight of the cylinder if the weight of the plunger is negligible. Cylinder W= 46kN A= 0.323m² W Oil SG 0.78 ↑ 4.6m ΠΟ F=? Plunger A= 0.00323m²
- Figure Q1 (a) shows the tank attached with piezometer tubes. The pressure gauge A is 2.3 kPa. The specific weight for the air is 12.0 N/m', the specific weight for gasoline is 6670 N/m³ and the specific weight for the glycerin is 12360 N/m³. Find the elevation level, ZB and Zc of the liquid (in meters) in the open piezometer tubes B and C. A B C 2 m Air 1.5 m Gasoline ZB Zc 1 m Glycerin Figure Q1 (a)The storage tank contains lubricating oil of specific weight (y). In one inclined side of the tank, there is a D m diameter circular inspection door, mounted on a horizontal shaft along the centre line of the gate. The oil level in the tank rests h m above the mounted shaft. (Please refer table 01 for relevant y, D and h values) Describe the hydrostatic force and centre of pressure with the aid of a free body diagram of the inspection door. Calculate the magnitude of the hydrostatic force and locate the centre of pressure. Estimate the moment that would have to be applied to the shaft to 450 open the gate. Stop If the oil level raised by 3 m from the current level, calculate the new moment required to open the gate. B specific weight = 7100 D = 0.7 m h = 25 m Figure 01The storage tank contains lubricating oil of specific weight (y). In one inclined side of the tank, there is a D m diameter circular inspection door, mounted on a horizontal shaft along the centre line of the gate. The oil level in the tank rests h m above the mounted shaft. (Please refer table 01 for relevant y, D and h values) Describe the hydrostatic force and centre of pressure with the aid of a free body diagram of the inspection door. Calculate the magnitude of the hydrostatic force and locate the centre of pressure. Estimate the moment that would have to be applied to the shaft to 450 open the gate. Stop If the oil level raised by 3 m from the current level, calculate the new moment required to open the gate. B specific weight = 7100 D = 0.7 m h = 25 m do last part only Figure 01
- Q3- The mercury manometer of figure indicates a differential reading of 0.30 m when the pressure in pipe A is 30-mm Hg vacuum. Determine the pressure in pipe B. Oil Water 0.50 m tB l0.15 m 0.30 m Mercury13. A U-tube differential manometer connects two pressure pipes A and B. Pipe A contains carbo tetrachloride having a specific gravity 1.594 under a pressure of 11.772 N/em and pipe B contains ofl of sp. gr. 0.8 under a pressure of 11.772 N/em. The pipe A lies 2.5 m above pipe B. Find the difference of pressure measured by mercury as fluid filling U-tube. 14. A differential manometer is connected at the two points A and B as shown in Fig. 2.25. At B air pressu is 7.848 N/cm (abs.), find the absolute pressure at A. [Ans. 31.36 cm of mercuryl (Ans, 6.91 Nicm) AIR WATER OIL Sp. gr.0.8 OIL Sp. gr. 0.8 50'cm 30 cm 100 am 60 cm 10 cm MERCURY Sp. gr.13.6 WATER Fig. 2.25 Fig. 2.26A U-tube differential manometer connects two pressure pipes A and B. Pipe A contains carbon tetrachloride having specific gravity 1.594 under a pressure of 117.72 kPa and pipe B contains oil of sp. gr. 0.8 under a pressure of 117.72 kPa. The pipe lies 2.5 m above pipe B. Find the difference of pressure measured by mercury as fluid filling U-tube.A. 120.58