I need help with step 2 of this problem i did step 1 please help me fill in these blanks. Step 2Use the half angle identity for sin² x.sin²(x)Hence,sin² x =1V = πTC==[x -X21-sin²(x)sin 2x1T2 0T= [(x - sin(x)(π2The volume of the solid of revolution is V =Submit Skip (you cannot come back)dxx ) - (0)]2 sin(x)x. For the region bounded by the graphs of the equations, find the following.y = sin(x), y = 0, x = 0, x = πExercise (a)the volume of the solid formed by revolving the region about the x-axisStep 1The region is bounded by the graphs of the equationsy = sin x, y = 0, x = 0, and x = π.V = πTherefore,AXFor the representative rectangle, the radius of the solid of revolution isR(x) = sin(x)= f*y=sin(x)sin (x)According to the disk method, the volume of the solid of revolution, when the area is revolved about the x axis is"b2= * [° [ R(x)] ².V = πA(sin(x))ke 100SOR(x)2dx.dx.

Solution of given question is written in below steps.

Use the half angle identity for sin² x. sin²(x) Hence, sin² x = ~ √₁² (₁²- V = π (1-sin²(x) 2 sin 2x 2 0 X X dx --x-sin 2 = [(x - sin(x) x )-(0)] The volume of the solid of revolution is V = 2 sin(x) X

Use the half angle identity for sin² x. sin²(x) Hence, sin² x = ~ √₁² (₁²- V = π (1-sin²(x) 2 sin 2x 2 0 X X dx --x-sin 2 = [(x - sin(x) x )-(0)] The volume of the solid of revolution is V = 2 sin(x) X

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter10: Analytic Geometry

Section10.1: The Rectangular Coordinate System

Problem 40E: Find the exact volume of the solid that results when the region bounded in quadrant I by the axes...

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Question

I need help with step 2 of this problem i did step 1 please help me fill in these blanks.

Step 2
Use the half angle identity for sin² x.
sin²(x)
Hence,
sin² x =
1
V = π
TC
==[x -
X
2
1-sin²(x)
sin 2x1T
2 0
T
= [(x - sin(x)
(π
2
The volume of the solid of revolution is V =
Submit Skip (you cannot come back)
dx
x ) - (0)]
2 sin(x)
x.

For the region bounded by the graphs of the equations, find the following.
y = sin(x), y = 0, x = 0, x = π
Exercise (a)
the volume of the solid formed by revolving the region about the x-axis
Step 1
The region is bounded by the graphs of the equations
y = sin x, y = 0, x = 0, and x = π.
V = π
Therefore,
AX
For the representative rectangle, the radius of the solid of revolution is
R(x) = sin(x)
= f*
y=sin(x)
sin (x)
According to the disk method, the volume of the solid of revolution, when the area is revolved about the x axis is
"b
2
= * [° [ R(x)] ².
V = π
A
(sin(x))
ke 100
SO
R(x)
2
dx.
dx.

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