What do you expect to see in a protein truncation test when there is a nonsense mutation? there will be no signal from the mutated protein the mutated protein will be less abundant (have a weaker signal) that the regular protein the mutated protein will be shorter than the regular protein there will be two bands on the gel for the mutated protein
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What do you expect to see in a protein truncation test when there is a nonsense mutation? What do you expect to see in a protein truncation test when there is a nonsense mutation? there will be no signal from the mutated protein the mutated protein will be less abundant (have a weaker signal) that the regular protein the mutated protein will be shorter than the regular protein there will be two bands on the gel for the mutated protein
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- A purified recombinant protein is analyzed for molecular weight by SDS-PAGE at pH 8.5. From the protein sequence deduced from the gene that was expressed in bacteria, the protein is expected to have a molecular weight of 44,000. However, the molecular weight of the protein is found by SDS-PAGE to be 52,000. Explain the reason or reasons for this difference in molecular weight. What calculation could you make to help explain this discrepancy?The following is a portion of a protein: met-trp-tyr-arg-gly-pro-thr-Various mutant forms of this protein have been recovered. Using the normal and mutant sequences, determine the DNA and mRNA sequences that code for this portion of the protein, and explain each of the mutations. a. met-trp- b. met-cys-ile-val-val-leu-gln- c. met-trp-tyr-arg-ser-pro-thr- d. met-trp-tyr-arg-gly-ala-val-ile-ser-pro-thr-The pre-mRNA transcript and protein made by several mutant genes were examined. The results are given below. Determine where in the gene a likely mutation lies: the promoter region, exon, intron, cap on mRNA, or ribosome binding site. a. normal-length transcript, normal-length nonfunctional protein b. normal-length transcript, no protein made c. normal-length transcript, normal-length mRNA, short nonfunctional protein d. normal-length transcript, longer mRNA, shorter nonfunctional protein e. transcript never made
- In the image below, the blue squiggly line represents a folded protein. There are two particular amino acids that are colored red and black in the protein. The structure of each of these two specific amino acids is shown in the indicated box. A mutation occurs in the gene that encodes the protein illustrated above. The result of this mutation is that one of the amino acids above is substituted with another. Specifically, the amino acid whose structure is shaded red above (the one on the left in the illustration) is replaced by the amino acid shown below. Use this information to answer the two questions that follow. Please answer these questions.  1. Based on this description, indicate which type of mutation occurred: missense, nonsense, silent, or indel 2. How would this mutation affect this protein's structure and function? Explain in 2-4 sentences. Be specific, and be sure to include details of these specific amino acids in your response. (I'm giving you the…In the absence of tryptophan and the trpD structural gene contains a frameshift insertion mutation, the structural genes will: [ Select ] ["No longer be expressed", "Be constantly expressed but the protein will be truncated and possibly non-functional", "Be constantly expressed but the protein will be longer and possibly non-functional"] In the presence of tryptophan and the trpD structural gene contains a frameshift insertion mutation, the structural genes will: [ Select ] ["No longer be expressed", "Be constantly expressed but the protein will be truncated and possibly non-functional", "Be constantly expressed but the protein will be longer and possibly non-functional"]A double mutant produced by uneven crossing-over contains two single nucleotide mutations that result in frame shifts and are separated by about 20 base pairs. The first is an insertion, while the second is a deletion. The amino acid sequences of the wildtype and mutant polypeptide in this region of the protein are as follows: Wildtype: Lys – Lys – Tyr – His – Gln – Trp – Thr – Cys – AsnDouble Mutant: Lys – Gln – Ile – Pro – Pro – Val – Asp – Met – Asn a) What are the original and double mutant mRNA sequences. You may find it useful to use the conventional symbols Y for pyrimidine, R for purine, N for any nucleotide, and H for A,C, or T. 2. b) Which nucleotide was inserted? 3. c) Which nucleotide was deleted?
- A very common molecular biology research method is to analyze cell or tissue homogenates by SDS-polyacrylamide gel electrophoresis and immunoblotting (Western blot). What can we learn about a protein of interest from this type of analysis? More than one answer is correct. Options: Determine the tertiary structure of the protein of interest. Determine or verify the molecular weight of the protein of interest. Compare the levels of the protein of interest in two different cell types. Determine the amino acid sequence from the product ion spectrum. Determine the intracellular binding partners of the protein of interest.You identify a mouse mutant that has hemophilia and is unable to properly clot blood. Your assays reveal that a novel clotting factor is absent from the blood of the mutant mice. You sequence the genome of the mutant mouse and determine that clotting factor proteins normally associated with hemophilia are all wildtype (no mutations), but the coding sequence of the novel protein differs by one amino acid compared to wildtype. When you synthesize the mutant protein in vitro, it has normal blood clotting activity. Your controls using other mutant hemophilia clotting proteins fail to clot blood in this assay. What would you say the mutant protein results in hemophelia?A scientist is researching GS1, an enzyme with a relative molecular mass (Mr) of 78,000 present in a bacterium. The scientist has isolated two mutant strains of the bacterium as described below. Strain A: In this strain the GS1 protein is completely non-functional. Analysis of strain A shows that it produces a shortened GS1 protein with an Mr of only 38,000. Strain B: This produces functional GS1, but the Kcat is somewhat reduced. Analysis shows it produces a lengthened form of GS1, with an Mr of about 86,000. Sequencing of the GS1 gene from strain B shows that it is identical to the wild type gene except for a single alteration (the replacement of one nucleotide by another). How might this account for the features of the GS1 protein produced by strain B?
- A scientist is researching GS1, an enzyme with a relative molecular mass (Mr) of 78,000 present in a bacterium. The scientist has isolated two mutant strains of the bacterium as described below. Strain A: In this strain the GS1 protein is completely non-functional. Analysis of strain A shows that it produces a shortened GS1 protein with an Mr of only 38,000. Strain B: This produces functional GS1, but the Kcat is somewhat reduced. Analysis shows it produces a lengthened form of GS1, with an Mr of about 86,000. What type(s) of mutation may have occurred in the GS1 gene in strain A?A scientist is researching GS1, an enzyme with a relative molecular mass (Mr) of 78,000 present in a bacterium. The scientist has isolated two mutant strains of the bacterium as described below. Strain A: In this strain the GS1 protein is completely non-functional. Analysis of strain A shows that it produces a shortened GS1 protein with an Mr of only 38,000. Strain B: This produces functional GS1, but the Kcat is somewhat reduced. Analysis shows it produces a lengthened form of GS1, with an Mr of about 86,000. The scientist determines the nucleotide sequence of the coding strand of the GS1 gene from strain A. It is identical to the GS1 sequence from the wild type gene except for a single change occurring approximately 1⁄3 of the way into the GS1 open reading frame. A small region of the GS1 sequence (including the site where the mutation occurs) from the wild type and mutant strains is shown below. Wild type TGTCCTCGGCCACAAGTTCTCTATC Strain A TGTCCTCGGCCACTAGTTCTCTATC How has this…You have isolated several E. coli mutants: Mutant #1 has a point mutation in the -10 region of the promoter of a structural gene encoding an enzyme needed for synthesis of the amino acid serine. Mutant #2 has a mutation in the -35 region in the promoter of the same gene. Mutant #3 is a double mutant with mutations in both the -10 and -35 region of the promoter of the same gene. Only Mutant #3 is unable to make serine. Why do you think this is so?