What is the average time to read or write a 512-byte sector for a typical disk rotating at 15,000 RPM? The advertised average seek time is 4 ms, the transfer rate is 100 MB/sec, and the controller overhead is 0.2 ms. Assume that the disk is idle so that there is no waiting time.
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- What is the average time to read or write a 512 bytes sector for a disk? The advertised average seek time is 5 ms, the transfer rate is 40 MB/sec, it rotates at 10,000 RPM, and the controller overhead is 0.1 ms. Assume the disk is idle so that there is no queuing delay. In addition, calculate the time assuming the advertised seek time is three times longer than the measured seek time.Calculate the access time for a disk having the size of 512 byte/sector and the seek time of 12ms. The rotational rate is 5700 RPM. The data transfer rate is 3MB/sec, and the the controller overhead is 1ms, you may even assume that there is no service time for the access.Suppose that a magnetic disk has an average seek time of 4 ms, a rotation rate of 5400 RPM, a transfer rate of 50 MB/second, a sector size of 512 bytes, and controller overhead of 2 ms. What is the average amount of time to read a single sector?
- Suppose that a disk drive rotates at 8000 RPM. It has an average seek time of 4 milliseconds. If its transfer rate is 15 Mbps, determine the average time it takes for a 15K byte request to be transferred from the time the disk starts the seek? From this, determine its throughput.What is the average time to read or write a 512-byte sector for a typical disk rotating at 15,000 RPM? The advertised average seek time is 4ms, the transfer rate is 100 MB/sec, and the controller overhead is 0.2ms. Assume that the disk is idle so that there is no waiting time. 512B sector, 15,000rpm, 4ms average seek time, 100MB/s transfer rate, 0.2ms controller overhead, idle diskConsider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side of platter: 30,000; number of sectors per track: 600; seek time: one ms for every hundred tracks traversed. Let the disk receive a request to access a random sector on a random track and assume the disk head starts at track 0. a. What is the average seek time? b. What is the rotational latency? c. What is the transfer time for a sector? d. What is the total average time to satisfy a request?
- The outer track 0 of a hard disk has a diameter of 8cm, the innermost track 36113 has a diameter of 4cm. For simplicity, let's assume that the head is moving at a constant speed of 2m/s. The hard disk rotates at 7200 rpm, the reading time of the sectors is negligible. How long does it take to change lanes from lane 0 to lane 36113? Enter the answer in milliseconds without decimal places.Consider a single-platter disk with the following parameters: rotation speed:7200 rpm; number of tracks on one side of platter: 30,000; number of sectors per track: 600; seek time: one ms for every hundred tracks traversed. Let the disk receive a request to access a random sector on a random track and assume the disk head starts at track 0. a. What is the average seek time? b. What is the average rotational latency? c. What is the transfer time for a sector?For a 5,000 RPM disk, assume its average seek time is 7 msec, and it has 100 MB/sec bandwidth; assume the sector size is 512 bytes. (In this problem, MB means 1,000,000 bytes.) How long does it take to access 2,048 bytes of contiguous data on average? What is the average throughput (bytes per second) if the user accesses 512 bytes for each I/O? Assume the data is perfectly aligned on the disk. How long does it take to access 1 MB of contiguous data (on average)? What is the average throughput (bytes per second) if the user accesses 1 MB for each I/O operations? Assume the data is perfectly aligned on the disk. Suppose a user expects his or her average throughput to reach 50% of the disk’s maximum bandwidth. Find the minimum I/O size needed to achieve this.
- Consider a disk with 2 MB/track, a rotation time of 10 msec, average seek time of 5 msec. On average, how long it takes to read 500 bytes from the disk?The disk specification in Figure 7.15 gives a data transfer rate of 60MB per second when reading from the disk, and 320MB per second when writing to the disk. Why are these numbers different? (Hint: Think about buffering.)Transfer rate of a disk drive can be no faster than the bit density (bits/track) times the rotational speed of the disk. Figure 7.15 gives a data transfer rate of 112GB/sec. Assume that the average track length of the disk is 5.5 inches. What is the average bit density of the disk?