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- IR Spectrum (CCl4 solution) U 4000 3000 100 80 60 40 20 JL 40 80 13C NMR Spectrum (100.0 MHz, CDCI, solution) % of base peak DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 2000 1693 v (cm¹) 155/157 120 160 m/e 160 7 1600 183/185 7.8 6 your 1200 120 800 Mass Spectrum C8H7OBr 280 solvent 80 M+= 198/200 200 240 expansion سلا 5 7.2 ppm 4 3 Problem 100 UV Spectrum max 258 nm (log₁0€ 4.2) solvent: ethanol 40 2 0 1 206 8 (ppm) TMS L 0 8 (ppm) 189¹3C NMR Spectrum (CDCI, 25MHz, ¹ H decoupled, solvent signals removed for clarity) Not sure how to interpret this C NMR. The molecular formula is C9H100 200 13C NMR Spectrum (CDCI3, 25 MHz, ¹H decoupled, solvent signals removed for clarity) d S 180 160 140 120 Ć 100 ppm 80 60 40 20 04000 100 80 60 20 % of base peak 3376 40 10 3000 59 13C NMR Spectrum (50.0 MHz, CDCI, solution) 173 proton decoupled 200 I 9 80 ¹H NMR Spectrum (200 MHz, CDCI, solution) DEPT CH₂ CH₂ CH4 IR Spectrum (liquid film) 2000 M+88 (<1%) 120 1600 v (cm¹) m/e 160 160 I I 8 7 mmm 1 120 200 240 6 1200 . Mass Spectrum L 800 1 5 C5H₁20 280 solvent L 80 4 problem 78 3 No significant UV absorption above 220 nm 40 Il 08 (ppm) 1 2 1 TMS 0 8 (ppm)
- I absorbance data for your methylene blue standards and determine the slope and y-intercept using the linear model equation Y-mX+ b. Once you have appropriately set up your spreadsheet, you should be able to predict the unknown concentration of methylene blue using the absorbance data that you collected. This unknown concentration should be plotted as a separate data point on your figure (with an appropriate label in the key) and should fall along the trendline if calculated properly. ...., create a scatter plot using the concentration Your figure should include the following: O Labelled axes (including titles and units) O A raw data "line" (raw data points) O A trendline that runs through the raw data O A separate data point for your unknown concentration of methylene blue O A key that clearly identifies the data set and the unknown O Figure number O Descriptive title Your spreadshcet should also include the following (which should not be part of your figure): O Slope O Y-intercept13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) C₂H₂ NO ₂ expansion 3.0 160 2.0 120 1.0 ppm 10 9 8 7 6 Determine the structure of the compound 5 solvent 80 4 40 3 2 08 (ppm) 1 TMS 0 8 (ppm)9 ¹H-NMR Spectra 2 M.F. = C₁₁H₁2O 15 15 -00 8 15 15 7 1 S 6 O) 15 15 5 PPM 4 21 -♡ 3 2 3) 0
- опанит 1715 1600 IR Spectrum 100 4000 (liquid film) 43 80 75 60 M 40 20 % of base peak 10 3000 40 C 13C NMR Spectrum (20.0 MHz, CDCI solution) proton decoupled 9 80 200 ¹H NMR Spectrum (100 MHz, CDCI, solution) 101 8 2000 v (cm¹) M** 132 120 160 m/e 160 7 6 1200 120 Mass Spectrum 200 240 280 800 C-H 5 C6H1203 solvent L 80 4 -CH3 No significant UV absorption above 220 nm 3 H-C-H u -CH3 40 2 59 TMS 0 1 8 (ppm) TMS 0 8 (ppm)IR Spectrum (liquid film) 4000 100 80 زار 60 40 20 stelldefels % of base peak 3000 40 57 91 13C NMR Spectrum (50.0 MHz, CDCI, solution) 92 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 1 2000 V (cm¹) 8 80 120 160 k 160 M+ m/e M 148 7 1600 200 IL 6 120 800 Mass Spectrum C11H16 280 solvent J 1200 240 expansion 7.5 I 1 5 L 80 7.0 I 4 1 ppm 3 Problem 97 UV Spectrum max 260 nm (log10 2.5) solvent methanol 40 I 2 0 1 8 (ppm) TMS L 0 8 (ppm) 2034000 IR Spectrum quid film) 100 80 60 40 YI 2248 41 10 3000 43 40 proton decoupled "C NMR Spectrum (150 MHz CDC, solution) 68 DEPT CH, CH, 1 CHT 9 200 ¹H NMR Spectrum (600 MHz, CDC, solution) M83 (<1%) 80 120 2000 v (cm) 8 m/e 160 160 2.3 L 7 1600 2.2 200 ryper 1200 6 ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ 120 Mass Spectrum 240 21 2.0 expansions (not to scale) 800 I CsH₂N 280 5 expansion 80 4 270 255 256 255 expansion No significant UV absorption above 220 nm 27.0 245 250 255 1.0 3 40 L 2 0 8 (ppm) 1 1 TMS L 1 0 8 (ppm) 10 ¹H-¹C me-HSQC Spectrum (600 MHz, CDC, solution) Black cross-peaks CH and CH Red cross-peaks CH₂ ppm 20 ¹H-"C HMBC Spectrum (600 MHz, CDC), solution) -22 -24 -26 -28 116 118 120 122 124 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0.6 ppm ppm 20 22 -24 26 28 -116 118 -120 122 -124 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0.6 ppm IR: List bands and possible/probable structural units responsible Band (cm³) Possible…
- 500 20 8.0 Interpret the 'H-NMR spectrum and assign the correct structure. Please be sure to explain your work. C₂H₁, CL 3.0 7.0 400 4.0 6.0 5.0 -B00 5.0 6.0 4.0 200 7.0 E 3.0 8.0 MA 20 100 9.0 1.0 10.0 (ppm) 가 O Hz 08 (ppm)4000 100 80 60 40 20 3410 tele 3000 40 10 43 ¹3C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 6.0 DEPT CH, CH₂ 1 CH 1 9 71 80 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) expansion ORGANIC STRUCTURES FROM SPECTRA 5.5 8 IR Spectrum (liquid film) 2000 M 86 (1%) 120 V (cm) m/e 160 1600 7 160 200 5.0 ppm 6 120 1200 J Mass Spectrum 240 800 5 CsH10O 280 solvent 80 4 exchanges with D.O 1 L 3 40 No significant UV absorption above 220 nm 2 E Q 115 08 (ppm) 1 TMS L 0 ō (ppm) IR: List bands and possible/probable structural units responsible Band (cm³) Possible stretches/functional groups MS: Molecular Formula, 13C NMR: 1 2 3 4 5 6 Chem. Shift (8) Type of C (sp), sp², carbonyl, etc.) ¹H NMR: 1 Chem. Shift (8) Multiplicity (singlet, doublet, etc.) IHD(DU)= 2 3 4 5 6 If you need more space, add any additional signal info here: (Show calculation) # of attached H's # of identical C's in signal Probable Type of H (methyl, aromatic, etc.) # of identical H's in signalDraw the structure of the compound identified by the simulated 'H NMR and ¹3C NMR spectra. The molecular formula of the compound is C₁0H₁2O. (Blue numbers next to the lines in the 'H NMR spectra indicate the integration values.) ¹H NMR 1H 2H 2H 2H 2H 3H IT 111 10 8 6 8 (ppm) 13C NMR III. 220 200 180 160 140 60 40 20 100 8 (ppm) Deduce the structure from the spectra. Select Draw More CHO 2 Ć Rings 120 80 Erase Q 2 Q