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8.17 LAB: Filter and sort a list
Write a
Ex: If the input is:
10 -7 4 39 -6 12 2
the output is:
2 4 10 12 39
For coding simplicity, follow every output value by a space. Do not end with newline.
Use Python, please.
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8.17.1: LAB: Filter and sort a list
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- //Need help fixing some issues with a project. PLEASE read below Write a Java program that implements both Linear Search and Binary Search. The program will take a collection of objects (generic type data) as input and print the number of comparisons needed to find a target element within that collection. You will create the following two Java classes:1. SearchCombo.java : Code for both linearSearch and binarySearch will be in this class. You may take help from the textbook Chapter 9, Section 9.1. However, note that the design requirements are different from the textbook code.•Both search methods must use the Comparable<T> interface and the compareTo() method.•Your program must be able to handle different data types, i.e., use generics.•For binarySearch, if you decide to use a midpoint computation formula that is different from the textbook, explain that formula briefly as a comment within your code. 2. Tester.java : This class will contain the main() method. The user will be…Assignment1: Analyse the case study given in chapter 3 Linked listAnswer the following questions from Library.java1. Write the different class names with class keyword chapter 3 Linked list : https://drive.google.com/file/d/1NRN_3Fx3smkjwv1jgG8hzaiGfnNfeeDb/view?usp=sharingdef small_index(items: list[int]) -> int:"""Return the index of the first integer in items that is less than its index,or -1 if no such integer exists in items.>>> small_index([2, 5, 7, 99, 6])-1>>> small_index([-5, 8, 9, 16])0>>> small_index([5, 8, 9, 0, 1, 3])3"""
- Add the following operation to the class orderedLinkedList: void mergeLists(orderedLinkedList<Type> &list1, orderedLinkedList<Type> &list2); //This function creates a new list by merging the //elements of list1 and list2. //Postcondition: first points to the merged list // list1 and list2 are empty Consider the following statements: orderedLinkedList<int> newList; orderedLinkedList<int> list1; orderedLinkedList<int> list2; Suppose list1 points to the list with the elements 2 6 7, and list2 points to the list with the elements 3 5 8. The statement newList.mergeLists(list1, list2); creates a new linked list with the elements in the order 2 3 5 6 7 8, and the object newList points to this list. Also, after the preceding statement executes, list1 and list2 are empty. 2. Write the definition of the function template mergeLists to implement the operation mergeLists.def items_in_sets(items: List) -> int: """Given a list of numbers that represent distinct items, how many ways are there to select a single item from the union of all sets? E.g., a list of [1, 2] would mean there are 2 sets of objects, containing 1 and 2 items each respectively." items_in_sets = None # YOUR CODE HERE #raise NotImplementedError() return items_in_setsin python class name: Runner function within a class: def __getitem__(self, lhs: Union[int. list[bool]]) -> Union[float, Runner]: The function should take a list[bool] and will return a new Runner object containing only the filtered values Example : c = Runner([1.0, 2.0, 3.0, 4.0, 2.0, 1.0]) filter = c > 2.0 print(filter) # Output: [False, True, True, False, False]) d = c[filter] print(d) # Output: Runner([3.0, 4.0])
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- ure.com/courses/90191/quizzes/234067/take ube Netflix O FMovies | Watch M. O My DLSU Login O Dashboard A gdrive taft 2 pts 5/5 Animo Space Support ? 2D-DP-8 a. void mysteryFunction (int myList[][5], int r, int c) { int i, j, k, curr, temp; for ( (1) ) for (i = 0; i < c; i++) { curr = i; for(j = i; j < c; j++) if(_(2)_) curr = j; temp = myList[k][i]; myList[k][i] = myList[k][curr]; myList[k][curr] = temp; int main() int i,j; { int input[2][5] = { {7, 2, 3, 15, 8}, {56, 4, 12, 5, 9}}; ampus mysteryFunction(input, 2, 5); for (i = 0; i < 2; i++) { for (j = 0; j < 5; j++) printf("%d ", input[i][j]); printf("\n"); ledia a Output: 2378 15 459 12 56 Given the code segment above, what should be the content of (1)_ in order to achieve the provided output? Assume the necessary libraries and functions are included and implemented. Encoding Instruction: Do NOT put any space in your answer. Answers not accepted by automatic checking of AnimoSpace due to non-compliance to encoding instructions will…write code in JAVA /* You have to use the following template to submit to Revel. Note: To test the code using the CheckExerciseTool, you will submit entire code. To submit your code to Revel, you must only submit the code enclosed between // BEGIN REVEL SUBMISSION // END REVEL SUBMISSION // BEGIN REVEL SUBMISSION /** Add an element to the beginning of the list */ public void addFirst(E e) { // Write your code here } /** Add an element to the end of the list */ public void addLast(E e) { // Write your code here } /** * Add a new element at the specified index in this list The index of the *head element is 0 */ public void add(int index, E e) { // Write your code here } /** * Remove the head node and return the object that is contained in the * removed node. */ public E removeFirst() { // Write your code here } /** * Remove the last node and return the object that is contained in the * removed node. */ public E removeLast() { // Write your code here } /** * Remove the element at the…class SLNode: """ Singly Linked List Node class DO NOT CHANGE THIS CLASS IN ANY WAY """ def __init__(self, value: object, next=None) -> None: self.value = value self.next = next from SLNode import *class SLLException(Exception): """ Custom exception class to be used by Singly Linked List DO NOT CHANGE THIS CLASS IN ANY WAY """ passclass LinkedList: def __init__(self, start_list=None) -> None: """ Initialize new linked list DO NOT CHANGE THIS METHOD IN ANY WAY """ self._head = SLNode(None) # populate SLL with initial values (if provided) # before using this feature, implement insert_back() method if start_list is not None: for value in start_list: self.insert_back(value) def __str__(self) -> str: """ Return content of singly linked list in human-readable form DO NOT CHANGE THIS METHOD IN ANY WAY """ out =…
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