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- Which of the following reactions is/are incorrect? (a) (b) „N2* Br Но H3O* Br2 (c) CUCN CN a & bRiedick the pr ducts/ifany that will be fomes bu Me gE no reachion dccurs, yeachion below woite R azter the geaction arrow 1+ AlCs) -y e praducts/if nay) d by-the neachion belain E no reachion Occurs , Warit Bredict the that will be forme Nh arter the renchion arrow reachin Colalag)t Mals)- t ー7 Bodict the products (if any) that will be forimed be the genchion below. na reachon Dccurs, write NR the reachin arrow axter PtClala9)+Mn(s)4b please answer (predict the outcome and explain briefly
- The coloriesS supe atanliquid was so 11. How does the addition of H3O* affect the following reaction equilibrium? 2CrO42- (aq, yellow) + 2H3O* (aq) -> Cr2O7²- (aq, orange) + 3H2O (1) a. The reaction shifts to the right and the concentration of CrO42- increases. b. The reaction shifts to the right causing the concentration of Cr2072 to decreases and the solution to turns yellow. c. The reaction shifts to the right resulting in a reduction in the concentration of H3O* and an increase in the concentration of Cr2O,2. d. The reaction shifts to the left and the concentration of CrO42 increases. e. The reaction shifts to the left and the concentration of CrO42 decreases.+ H (a) CuCN (b) CaCO3 (c) Ag₂CO3 (d) PbBr₂ (e) Y(OH)3 Periodic Table B W Chapter... Supporting Materials Additional Materiala [Ca²+] = 5.2 x 104 M, [CO32- ] = 6.5x 10-6 M * G Please use the values in the resources listed below instead of the textbook values. The following concentrations are found in mixtures of ions in equilibrium with slightly soluble solids. From the concentrations given, calculate Ksp for each of the slightly soluble solids indicated. [Cu] = 1.9x10-10 M, [CN] = 1.9x10-¹0 M [Ag+] = 1.8x10-5 M, [CO32] = 2.7x10-² M [Pb²+] = 1.2x 10-2 M, [Br] = 2.4x10-2 M [Y³+] = 3.5x 10-16 M, [OH-] = 6.6x 10-³ M Constants and Factors №. webassign.net ● F 893 Supplemental Data L C C a Ⓒ + D rA 4.912-g sample of a petroleum product was burnedin a tube furnace, and the SO2produced was collectedin 3% H2O2.Reaction:SO2(g)+H2O2→H2SO4A 25.00-mL portion of 0.00873 M NaOH was introducedinto the solution of H2SO4, following whichthe excess base was back-titrated with 15.17 mL of0.01102 M HCl. Calculate the sulfur concentrationin the sample in parts per million.
- (a) MeMgBr (excess) H3O* workup (b) CN NaOH 0 °C (e) Ph. (d) H,O* (cat.) OH Он (e) MeMgBr (excess) HO D,O* workup Predict the product(s) of the following reactions. If you expect no reaction to occur, then you may write “no reaction."4. (4a) + NaHCO, - H2O + (4b)_ 5. CH;COOH + CH;CH2OCOCH3 + H2O -COCH3 6. (6a) (6b) - + H2O(b) Calculate the pH of 0.0005 mol dm-3 ethanoic acid when its pKa = 4.75 and explain the assumptions made in the calculations CH3COOH(aq) à CH3COO-(aq) + H+(aq) Ka = pH = 3.1 (a) Define and write the expression of Kw for the dissociation of water (H2O). Kw is the ____________________ _____________ of _________________ Kw = (b) Calculate the pH of 0.1 mol dm-3 potassium hydroxide (KOH(aq)) pH = 10. Explain briefly the effect of temperature on Kw.
- HO + Oz ta) 6. Directions: To a test tube containing 3 ml of 3% H.O, (hydrogen peroxide), add 0.1 g (a small scoop) of the catalyst KI. (Note that a catalyst affects the rate of a reaction but is not involved in the overall reaction for the process). Observations: 7. C2HeO + O2 (9) - CO2 (a) + Directions: Add 2 ml of a saturated calcium acetate solution to an evaporating dish. To the dish add 15 ml of ethanol and swirl the contents. Pour off any excess liquid and ignite the remaining contents with a match. Sprinkle some boric acid on the flame. Although the reaction is actually more complex, the reaction you will balance and classify is the reaction between only ethanol (C,HSOH) and oxygen. Observations:Keeping in mind the leveling effect, can the following species be used as a reactant in ethanamine (CH,CH,NH,)? (1) ©OH (c) O, ´CH3 (d) ONH2 (e) O ʼNH4 (a) c (b) HCIFind Ecell = 0.48V. Use dhis regult along with the equilibrium conlentretion of Lu“ (mol/L) wheun 24. C[Cu (NH3), ) = 0.10 mol /L and [N H3] = 6.1 mol/h to calceulate the cqnillibriem Lonstant for the formation of [cu(NH3),]"]