You’re holding a hose at waist height and spraying water horizontally with it. The hose nozzle has a diameter of 1.80 cm, and the water splashes on the ground a distance of 0.970 m horizontally from the nozzle. Suppose you now constrict the nozzle to a diameter of 0.750 cm; how far horizontally from the nozzle will the water travel before hitting the ground? (Ignore air resistance.)

A firefighter mounts the nozzle of his fire hose a distance 32.1 m away from the edge of a burning building so that it sprays from ground level at a 45° angle above the horizontal. After quenching a hotspot at a height of 9.33 m, the firefighter adjusts the nozzle diameter so that the water hits the building at a height of 17.5 m. By what factor was the nozzle diameter changed? Assume that the flow rate of water through the hose stays the same, and treat the water as an ideal fluid. factor by which the hose diameter changed:

A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of ?1=1.07 m/s . At a lower point, the diameter of the stream has decreased by a factor of 0.787 . What is the vertical distance ℎbetween these two points?

A tank in the form of a right-circular cylinder of radius 0.4 m and height 3 m is standing on end. When water leaks through a hole, friction and contraction of the stream near the hole reduce the volume of the water leaving the tank per second to CA,√2gh. If the tank is initially full of water, and water leaks from a circular hole of radius 17.5 mm at its bottom, determine a differential equation for the height h of the water at time t. Ignore friction and contraction of water at the hole, that is let c = 1. (Assume the acceleration due to gravity g is 9.8 m/s². Round your numeric value to five decimal places.) dh dt = eBook -3 8.47392 10 3 √h