y(x2 + y? – 1)dx + x(x² + y² + 1)dy = 0 У (2x2 — ху + 1)dx + (х — у)dy %3D 0 x2 + y2 dy 1 dx 3y2(x3+y3)2 ||
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Obtain the solution of the following differential equations.
please answer the 3 problems
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- how would I take the partial derrivitive of this equation, I cannot use the chain Rule as we have not learned it yet, the teacher said we would have to manipulate the equation somehow. f(x,y) = x2 ln(2y3 -x4)equation from C is -x+2y-z=0elimination of first degree variable: 3x+y-z=11x+3y-z=13x+y-3z=11