Chapter 1.1, Problem 20E

(a)

To determine

To find:the number ofstudents in the two way table and the percent of thesmoking students

Answer to Problem 20E

Table describes total 5375 students.18.7% of students smoke.

Explanation of Solution

Given:

  

Calculation:

Table describes total 5375 students. 18.7% of students smoke.

	Parent’s Smoking Behaviour
	Neither Parent Smoke	One Parent Smoke	Both Parents Smoke	Total	Percent
Student does not smoke	1168	1823	1380	4371	$\begin{array}{l}\frac{4371}{5375}\times 100\\ =81.3\%\end{array}$
Students smoke	188	416	400	1004	$\begin{array}{l}\frac{1004}{5375}\times 100\\ =18.7\%\end{array}$
Total	1356	2239	1780	5375
Percent	25.2%	41.7%	33.1%

Conclusion:

Hence,table describes total 5375 students. 18.7% of students smoke.

(b)

To determine

To explain: the marginal distribution of parents smoking behaviour.

Answer to Problem 20E

Marginal Distribution Table
Parents Smoking Behaviour	Student Does not Smoke	Student Smokes	Row Total (count)	Percentage
Neither Parent Smoke	1168	188	1356	$\frac{1356}{5375}$	0.2523	$\frac{1356}{5375}\times 100$	36.8%
One Parent Smoke	1823	416	2239	$\frac{2238}{5375}$	0.4166	$\frac{2238}{5375}\times 100$	24.1%
Both Parents Smoke	1380	400	1780	$\frac{1780}{5375}$	0.3312	$\frac{1780}{5375}\times 100$	39.1%
Total	4371	1004	5375		1		100

Explanation of Solution

Formula Used:

Marginal Distribution Percentage:

  $\frac{\text{Row Total}}{\text{Table Total}}\times 100$

Calculation:

The marginal distribution of parents smoking habit is shown in table below:

Marginal Distribution Percentage:

  $\frac{\text{Row Total}}{\text{Table Total}}\times 100$

Table Total=5375

Marginal Distribution Table
Parents Smoking Behaviour	Student Does not Smoke	Student Smokes	Row Total (count)	Percentage
Neither Parent Smoke	1168	188	1356	$\frac{1356}{5375}$	0.2523	$\frac{1356}{5375}\times 100$	36.8%
One Parent Smoke	1823	416	2239	$\frac{2238}{5375}$	0.4166	$\frac{2238}{5375}\times 100$	24.1%
Both Parents Smoke	1380	400	1780	$\frac{1780}{5375}$	0.3312	$\frac{1780}{5375}\times 100$	39.1%
Total	4371	1004	5375		1		100

Conclusion:

Hence,the marginal distribution of parents smoking behaviour is shown.