Chapter 11.1, Problem 1PSA

a

To determine

To find : The area of figure shown in part a

Answer to Problem 1PSA

The area is $A=207$

Explanation of Solution

Given information : The following information has been given

Length of bigger rectangle $l_1=18$

Width of bigger rectangle $w_1=14$

Length of smaller rectangle $l_2=5$

Width of smaller rectangle $w_2=9$

Formula used : The area of any rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)$

Calculation : We know that the area of the given rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)-(lengt{h}_2)(widt{h}_2)$

Hence, substituting the values from the given information, we get

  $A=(18)(14)-(5)(9)=207$

Thus, we get

  $A=207$

b

To determine

To find : The area of figure shown in part b

Answer to Problem 1PSA

The area is $A=102$

Explanation of Solution

Given information : The following information has been given

Length of bigger rectangle $l_1=15$

Width of bigger rectangle $w_1=8$

Length of smaller rectangle $l_2=4$

Width of smaller rectangle $w_2=3$

Length of smaller rectangle $l_3=3$

Width of smaller rectangle $w_3=2$

Formula used : The area of any rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)$

Calculation : We know that the area of any rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)-[(lengt{h}_2)(widt{h}_2)-(lengt{h}_3)(widt{h}_3)]$

Hence, substituting the values from the given information, we get

  $A=(15)(8)-[(4)(3)-(3)(2)]=102$

Thus, we get

  $A=102$

c

To determine

To find : The area of figure shown in part c

Answer to Problem 1PSA

The area is $A=80$

Explanation of Solution

Given information : The following information has been given

Length of rectangle $l=10$

Width of rectangle $w=8$

Formula used : The area of any rectangle will be

  $A=(lengt{h}_1)(widt{h}_1)$

Calculation : We know that the area of any rectangle will be

  $A=(length)(width)$

Hence, substituting the values from the given information, we get

  $A=(10)(8)=80$

Thus, we get

  $A=80$