World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 12, Problem 33A

(a)

Interpretation Introduction

Interpretation:

The total number of valence electrons is to be calculated in the given molecule.

Concept introduction:

The valence electrons are the electrons which are present in last shell and available for bond formation.

(a)

Expert Solution
Check Mark

Answer to Problem 33A

Total number of valence electrons in CBr4=32

Explanation of Solution

Number of valence electrons in carbon=4

Number of valence electrons in each bromine=7

Therefore, Total number of valence electrons in CBr4=4+7×4

  =32

(b)

Interpretation Introduction

Interpretation:

The total number of valence electrons is to be calculated in the given molecule.

Concept introduction:

The valence electrons are the electrons which are present in last shell and available for bond formation.

(b)

Expert Solution
Check Mark

Answer to Problem 33A

Total number of valence electrons in NO2=17

Explanation of Solution

Number of valence electrons in nitrogen=4

Number of valence electrons in each oxygen=7

Therefore, Total number of valence electrons in NO2=5+6×2

  =17

(c)

Interpretation Introduction

Interpretation:

The total number of valence electrons is to be calculated in the given molecule.

Concept introduction:

The valence electrons are the electrons which are present in last shell and available for bond formation.

(c)

Expert Solution
Check Mark

Answer to Problem 33A

Total number of valence electrons in C6H6=30

Explanation of Solution

Number of valence electrons in each carbon=4

Number of valence electrons in each hydrogen=1

Therefore, Total number of valence electrons in C6H6=4×6+1×6

  =30

(a)

Interpretation Introduction

Interpretation:

The total number of valence electrons is to be calculated in the given molecule.

Concept introduction:

The valence electrons are the electrons which are present in last shell and available for bond formation.

(a)

Expert Solution
Check Mark

Answer to Problem 33A

Total number of valence electrons in H2O2=14

Explanation of Solution

Number of valence electrons in each hydrogen=1

Number of valence electrons in each oxygen=6

Therefore, Total number of valence electrons in H2O2=2×1+6×2

  =14

Chapter 12 Solutions

World of Chemistry, 3rd edition

Ch. 12.2 - Prob. 4RQCh. 12.2 - Prob. 5RQCh. 12.2 - Prob. 6RQCh. 12.2 - Prob. 7RQCh. 12.3 - Prob. 1RQCh. 12.3 - Prob. 2RQCh. 12.3 - Prob. 3RQCh. 12.3 - Prob. 4RQCh. 12.4 - Prob. 1RQCh. 12.4 - Prob. 2RQCh. 12.4 - Prob. 3RQCh. 12.4 - Prob. 4RQCh. 12.4 - Prob. 5RQCh. 12 - Prob. 1ACh. 12 - Prob. 2ACh. 12 - Prob. 3ACh. 12 - Prob. 4ACh. 12 - Prob. 5ACh. 12 - Prob. 6ACh. 12 - Prob. 7ACh. 12 - Prob. 8ACh. 12 - Prob. 9ACh. 12 - Prob. 10ACh. 12 - Prob. 11ACh. 12 - Prob. 12ACh. 12 - Prob. 13ACh. 12 - Prob. 14ACh. 12 - Prob. 15ACh. 12 - Prob. 16ACh. 12 - Prob. 17ACh. 12 - Prob. 18ACh. 12 - Prob. 19ACh. 12 - Prob. 20ACh. 12 - Prob. 21ACh. 12 - Prob. 22ACh. 12 - Prob. 23ACh. 12 - Prob. 24ACh. 12 - Prob. 25ACh. 12 - Prob. 26ACh. 12 - Prob. 27ACh. 12 - Prob. 28ACh. 12 - Prob. 29ACh. 12 - Prob. 30ACh. 12 - Prob. 31ACh. 12 - Prob. 32ACh. 12 - Prob. 33ACh. 12 - Prob. 34ACh. 12 - Prob. 35ACh. 12 - Prob. 36ACh. 12 - Prob. 37ACh. 12 - Prob. 38ACh. 12 - Prob. 39ACh. 12 - Prob. 40ACh. 12 - Prob. 41ACh. 12 - Prob. 42ACh. 12 - Prob. 43ACh. 12 - Prob. 44ACh. 12 - Prob. 45ACh. 12 - Prob. 46ACh. 12 - Prob. 47ACh. 12 - Prob. 48ACh. 12 - Prob. 49ACh. 12 - Prob. 50ACh. 12 - Prob. 51ACh. 12 - Prob. 52ACh. 12 - Prob. 53ACh. 12 - Prob. 54ACh. 12 - Prob. 55ACh. 12 - Prob. 56ACh. 12 - Prob. 57ACh. 12 - Prob. 58ACh. 12 - Prob. 59ACh. 12 - Prob. 60ACh. 12 - Prob. 61ACh. 12 - Prob. 62ACh. 12 - Prob. 63ACh. 12 - Prob. 64ACh. 12 - Prob. 1STPCh. 12 - Prob. 2STPCh. 12 - Prob. 3STPCh. 12 - Prob. 4STPCh. 12 - Prob. 5STPCh. 12 - Prob. 6STPCh. 12 - Prob. 7STPCh. 12 - Prob. 8STPCh. 12 - Prob. 9STP
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