Answer 356 Explanation Given information: The expression, 284 − ( 93 − 165 ) Concept used: For Order of Operation, we will use PEMDAS rule. Symbols are representing: P − parenthesis, E − exponent, M − multiplication, D − division, A − addition and S − subtraction. If grouping symbols such as parenthesis are present, simplify expressions within those first, starting with the innermost set. Evaluate exponential expressions or absolute values in order from left to right. Multiply or divide in order from left to right. Add or subtract in order from left to right. If there is no grouping symbols or no exponents, we multiply or divide and then add or subtract in the order from left to right. Calculation: To simplify the expression 284 − ( 93 − 165 ) , first subtract the numbers inside the parenthesis and then simplify further by subtracting the resulting numbers as shown below, 284 − ( 93 − 165 ) = 284 − ( 93 − 165 ) = 284 − ( − 72 ) = 284 + 72 = 356 Thus, the given expression simplifies to 356 .

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 4, Problem 6MS

To determine

To simplify expression 284−(93−165)

Expert Solution & Answer

Answer to Problem 6MS

356

Explanation of Solution

Given information:

The expression, 284−(93−165)

Concept used:

For Order of Operation, we will use PEMDAS rule.

Symbols are representing:

P − parenthesis, E − exponent, M − multiplication,

D − division, A − addition and S − subtraction.

If grouping symbols such as parenthesis are present, simplify expressions within those first, starting with the innermost set.
Evaluate exponential expressions or absolute values in order from left to right.
Multiply or divide in order from left to right.
Add or subtract in order from left to right.

If there is no grouping symbols or no exponents, we multiply or divide and then add or subtract in the order from left to right.

Calculation:

To simplify the expression 284−(93−165) , first subtract the numbers inside the parenthesis and then simplify further by subtracting the resulting numbers as shown below,

284−(93−165)=284−(93−165)=284−(−72)=284+72=356

Thus, the given expression simplifies to 356 .

Chapter 4, Problem 5MS

Chapter 4, Problem 7MS

Chapter 4 Solutions

Algebra: Structure And Method, Book 1

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Prob. 7MRE Ch. 4.8 - Prob. 8MRE Ch. 4.9 - Prob. 1OE Ch. 4.9 - Prob. 2OE Ch. 4.9 - Prob. 1P Ch. 4.9 - Prob. 2P Ch. 4.9 - Prob. 3P Ch. 4.9 - Prob. 4P Ch. 4.9 - Prob. 5P Ch. 4.9 - Prob. 6P Ch. 4.9 - Prob. 7P Ch. 4.9 - Prob. 8P Ch. 4.9 - Prob. 9P Ch. 4.9 - Prob. 10P Ch. 4.9 - Prob. 11P Ch. 4.9 - Prob. 12P Ch. 4.9 - Prob. 13P Ch. 4.9 - Prob. 1MRE Ch. 4.9 - Prob. 2MRE Ch. 4.9 - Prob. 3MRE Ch. 4.9 - Prob. 4MRE Ch. 4.9 - Prob. 5MRE Ch. 4.9 - Prob. 6MRE Ch. 4.9 - Prob. 7MRE Ch. 4.9 - Prob. 8MRE Ch. 4.9 - Prob. 9MRE Ch. 4.9 - Prob. 10MRE Ch. 4.9 - Prob. 11MRE Ch. 4.9 - Prob. 12MRE Ch. 4.10 - Prob. 1P Ch. 4.10 - Prob. 2P Ch. 4.10 - Prob. 3P Ch. 4.10 - Prob. 4P Ch. 4.10 - Prob. 5P Ch. 4.10 - Prob. 6P Ch. 4.10 - Prob. 7P Ch. 4.10 - Prob. 8P Ch. 4.10 - Prob. 9P Ch. 4.10 - Prob. 10P Ch. 4.10 - Prob. 11P Ch. 4.10 - Prob. 12P Ch. 4.10 - Prob. 13P Ch. 4.10 - Prob. 14P Ch. 4.10 - Prob. 15P Ch. 4.10 - Prob. 16P Ch. 4.10 - Prob. 1ST Ch. 4.10 - Prob. 2ST Ch. 4.10 - Prob. 3ST Ch. 4.10 - Prob. 4ST Ch. 4 - Prob. 1CR Ch. 4 - Prob. 2CR Ch. 4 - Prob. 3CR Ch. 4 - Prob. 4CR Ch. 4 - Prob. 5CR Ch. 4 - Prob. 6CR Ch. 4 - Prob. 7CR Ch. 4 - Prob. 8CR Ch. 4 - Prob. 9CR Ch. 4 - Prob. 10CR Ch. 4 - Prob. 11CR Ch. 4 - Prob. 12CR Ch. 4 - Prob. 13CR Ch. 4 - Prob. 14CR Ch. 4 - Prob. 15CR Ch. 4 - Prob. 16CR Ch. 4 - Prob. 17CR Ch. 4 - Prob. 18CR Ch. 4 - Prob. 1CT Ch. 4 - Prob. 2CT Ch. 4 - Prob. 3CT Ch. 4 - Prob. 4CT Ch. 4 - Prob. 5CT Ch. 4 - Prob. 6CT Ch. 4 - Prob. 7CT Ch. 4 - Prob. 8CT Ch. 4 - Prob. 9CT Ch. 4 - Prob. 10CT Ch. 4 - Prob. 11CT Ch. 4 - Prob. 12CT Ch. 4 - Prob. 13CT Ch. 4 - Prob. 14CT Ch. 4 - Prob. 15CT Ch. 4 - Prob. 16CT Ch. 4 - Prob. 17CT Ch. 4 - Prob. 18CT Ch. 4 - Prob. 19CT Ch. 4 - Prob. 20CT Ch. 4 - Prob. 21CT Ch. 4 - Prob. 22CT Ch. 4 - Prob. 1CLR Ch. 4 - Prob. 2CLR Ch. 4 - Prob. 3CLR Ch. 4 - Prob. 4CLR Ch. 4 - Prob. 5CLR Ch. 4 - Prob. 6CLR Ch. 4 - Prob. 7CLR Ch. 4 - Prob. 8CLR Ch. 4 - Prob. 9CLR Ch. 4 - Prob. 10CLR Ch. 4 - Prob. 11CLR Ch. 4 - Prob. 12CLR Ch. 4 - Prob. 13CLR Ch. 4 - Prob. 14CLR Ch. 4 - Prob. 15CLR Ch. 4 - Prob. 16CLR Ch. 4 - Prob. 17CLR Ch. 4 - Prob. 18CLR Ch. 4 - Prob. 19CLR Ch. 4 - Prob. 20CLR Ch. 4 - Prob. 21CLR Ch. 4 - Prob. 22CLR Ch. 4 - Prob. 23CLR Ch. 4 - Prob. 24CLR Ch. 4 - Prob. 25CLR Ch. 4 - Prob. 26CLR Ch. 4 - Prob. 27CLR Ch. 4 - Prob. 28CLR Ch. 4 - Prob. 29CLR Ch. 4 - Prob. 30CLR Ch. 4 - Prob. 31CLR Ch. 4 - Prob. 32CLR Ch. 4 - Prob. 33CLR Ch. 4 - Prob. 34CLR Ch. 4 - Prob. 35CLR Ch. 4 - Prob. 36CLR Ch. 4 - Prob. 37CLR Ch. 4 - Prob. 38CLR Ch. 4 - Prob. 39CLR Ch. 4 - Prob. 40CLR Ch. 4 - Prob. 1MS Ch. 4 - Prob. 2MS Ch. 4 - Prob. 3MS Ch. 4 - Prob. 4MS Ch. 4 - Prob. 5MS Ch. 4 - Prob. 6MS Ch. 4 - Prob. 7MS Ch. 4 - Prob. 8MS Ch. 4 - Prob. 9MS Ch. 4 - Prob. 10MS Ch. 4 - Prob. 11MS Ch. 4 - Prob. 12MS Ch. 4 - Prob. 13MS Ch. 4 - Prob. 14MS Ch. 4 - Prob. 15MS Ch. 4 - Prob. 16MS Ch. 4 - Prob. 17MS Ch. 4 - Prob. 18MS Ch. 4 - Prob. 19MS Ch. 4 - Prob. 20MS Ch. 4 - Prob. 21MS Ch. 4 - Prob. 22MS Ch. 4 - Prob. 23MS Ch. 4 - Prob. 24MS Ch. 4 - Prob. 25MS Ch. 4 - Prob. 26MS Ch. 4 - Prob. 27MS Ch. 4 - Prob. 28MS Ch. 4 - Prob. 29MS Ch. 4 - Prob. 30MS Ch. 4 - Prob. 31MS

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