Concept explainers
To find: three consecutive odd integers such that twice the smallest is 3 more than the greatest integer
Answer to Problem 11P
The required answer is: consecutive odd integers are -7, -5 and -3
Explanation of Solution
Calculation:
Let the first odd integer be x
Let the second odd integer be x+2
Let the third odd integer be x+4
(Twice the smallest is 3 more than the greatest integer)
(Subtract x from both sides)
(Simplify)
First integer:
Second integer:
Third integer:
Therefore the consecutive odd integers are -7, -5 and -3.
Chapter 4 Solutions
Algebra: Structure And Method, Book 1
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