Concept explainers
To find: four consecutive integers whose sum is twice the cube of 5
Answer to Problem 7P
The required answer is: consecutive integers are 61, 62, 63 and 64
Explanation of Solution
Calculation:
Let the first integer be x
Let the second integer be x+1
Let the third integer be x+2
Let the fourth integer be x+3
(Sum of four consecutive integers is twice the cube of 5)
(Subtract 6 from both sides)
(Divide 4 on both sides)
(Simplify)
First integer:
Second integer:
Third integer:
Fourth integer:
Therefore the consecutive integers are 61, 62, 63 and 64.
Chapter 4 Solutions
Algebra: Structure And Method, Book 1
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