Chapter 7.6, Problem 2CE

To determine

Sketch a graph to check the variation of population and no. of bacteria are exponentially decrease and increase or not.

Answer to Problem 2CE

The solution is

    

As we can see in the figure the population isn’t decrease exponentially, its decrease linearly. In the second figure the bacteria are exponentially increases.

Explanation of Solution

Given: The data is given

  $\begin{array}{cc}Year after 1989& \begin{array}{l}Population of \\ Moddville\end{array}\\ 1& 207\\ 2& 200\\ 3& 193\\ 4& 186\\ 5& 179\end{array}$   $\begin{array}{cc}\begin{array}{l}Hour after start\\ of\exp eriment\end{array}& \begin{array}{l}Number of \\ Bacteria\end{array}\\ 1& 500\\ 2& 705\\ 3& 994\\ 4& 1402\\ 5& 1977\end{array}$

Calculation:

Using MATLAB just plot the data and check the variation of population and number of bacteria.

program:

clc
clear
close all
years=[1 2 3 4 5];
hours=[1 2 3 4 5];
population=[207 200 193 186 179];
Nbact=[500 705 994 1402 1977];
figure(1)
plot(years,population,'linewidth',1.2)
set(gca,'linewidth',1.2,'fontsize',12);
xlabel('Years')
ylabel('Population of Muddville')
axis square
figure(2)
plot(hours,Nbact,'linewidth',1.2)
set(gca,'linewidth',1.2,'fontsize',12,'YTick',(500:250:2000));
xlabel('Hours')
ylabel('No. of bacteria')
axis square

Query:

• First, we have defined the data value in the separate matrix.
• Then plot the graph.
• Check the variation of population and number of bacteria.