The following truth table has 4 inputs, w, x, y, z and 1 output F. Using a Kamaugh map, find a simplified Boolean expression for F. Here "X" represents "don't care" outputs wx ly z F 000 00 00 0 1 1 00 1 00 00 1 11 01 0 о 0 01 0 1 1 01 10 0 01 1 هم 1 X 1000 1 1001 1 10 10 1 101 1 1100 X 1 x 11 01 X 11 10 1 11 11 1
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- For the truth table above where wx input is down and the y input is across, which one of these is a simplified expression? F(w,x,y)=w+x F(w,x,y)=w'(w+x+y') F(w,x,y)=y+w+x F(w,x,y)=w'+w+x F(w,x,y)=w'+xy'Let the Boolean function F(x, y, z) = x‾.(y + z) A. Find the values of the Boolean function F (you may copy the following table and fill it) B. Represent F using the sum-of-products expansion form x y z x‾ y + z x‾.(y + z) 1 1 1 1 1 0 1 0 1 1 0 0 0 1 1 0 1 0 0 0 1 0 0 0Transcribed Image Text What is a trap state? Encircle the stable states in the following excitation table (Table 4). X is the excitation variable and Y Yo are secondary outputs. Identify and mark the trap state, if there is any. Table 4 Y,Y. Vyo 00 00 00 01 11 00 11 10 10 10 01 10 1.
- Do it correctly not same copied. Given the following Boolean equations entered by the truth table, please provide a schematic with logic gates: A = W'X'Y'Z + W'X'YZ' + W'X'YZ + W'XY'Z + W'XYZ' + W'XYZ + WX'Y'Z' + WX'Y'Z B = W'X'Y'Z' + W'X'Y'Z + W'X'YZ' + W'X'YZ + W'XY'Z + W'XYZ + WX'Y'Z' + W'X'Y'Z C = W'X'Y'Z' + W'X'Y'Z + W'X'YZ + W'XY'Z' + W'XY'Z + W'XYZ' + W'XYZ + WX'Y'Z' + WX'Y'Z D = W'X'Y'Z' + W'X'YZ' + W'X'YZ + W'XY'Z + W'XYZ' + WX'Y'Z + WX'Y'Z E = W'X'Y'Z' + W'X'YZ' + W'XYZ' + WX'Y'Z' F = W'X'Y'Z' + W'XY'Z' + W'XY'Z + W'XYZ' + WX'Y'Z' + WX'Y'Z G = W'X'Y'Z' + W'X'YZ + W'XY'Z' + W'XY'Z + W'XYZ' + WX'Y'Z' + WX'Y'Z.Is my truth table correct for the following conditions? If W is greater than X , then A is 1, B and C are 0. If W equals X, then B is 1, A and C are 0. If W is less than X, C is 1, A and B are 0.Given the Boolean function F below, reduce it to a simplest form using identity laws. Provide step-by-step activities along with the identity used at each step. F(X,Y,Z)= X’Y’Z + X’YZ + XY’Z + XYZ
- What is F in SOP in expression F(w,x ,y z) = Σ(2, 4, 6, 8, 10, 12): d(0, 1, 3, 5, 7, 9, 11, 13, 14, 15) a. 1 b. F = (wx) + (yz) c. F = (xyz) + (wz) + (yz) d. F = (wy) + (xz)Simplify the following Boolean expression. F(W, X, Y, Z) = X*Y + W*X*Y*!Z + !X*Y =Build truth tables for the following three wffs: 1. (A ⊃ (~A v ~B)) ⊃ (A v ~ B) 2. ( (A v B) & ((~A ⊃ B) ⊃ B)) ⊃ (A ⊃ ~B) 3. (A ⊃ B) v (~B v (A ⊃ ~ B))
- Choose the correct output for F base on the black diagram. A.) 0000001100010011 B.) 0000010001000101Write a truth table for F(abc) = (a+b)' (b+c')Please explain all steps: What Boolean equation is represented by the following K-Maps: a) ~y~z ~yz yz y~z ~x 1 1 1 x 1 1 1 1 b) ~y~z ~yz yz y~z ~w~x 1 1 ~wx 1 1 wx 1 w~x 1 1 c) ~y~z ~yz yz y~z ~w~x 1 1 1 1 ~wx 1 1 wx 1 1 1 1 w~x 1 1 d) ~y~z ~yz yz y~z ~w~x 1 1 ~wx 1 1 1 wx 1 1 w~x 1 1 1