Explanation Given information: A person’s blood pressure, p, in millimetres of mercury (mm Hg) is given, for t seconds, by p = 100 + 20 sin ( 2.5 π t ) Fact used: For a sine function, − 1 ≤ sin x ≤ 1 Calculation: p = 100 + 20 sin ( 2.5 π t ) (Given) ⇒ p − 100 20 = sin ( 2.5 π t ) Since, − 1 ≤ sin x ≤ 1 , − 1 ≤ sin ( 2 To determine (b) To calculate: The time between successive maxima . To determine (c) To graph: The blood pressure against time.

6th Edition

ISBN: 9781119399353

Author: DA

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

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Question

Chapter 4.3, Problem 60P

To determine

(a)

To calculate:

The maximum and minimum values of blood pressure.

To determine

(b)

To calculate:

The time between successive maxima.

To determine

(c)

To graph:

The blood pressure against time.

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Chapter 4.3, Problem 59P

Chapter 4.4, Problem 1P

Chapter 4 Solutions

EBK APPLIED CALCULUS, ENHANCED ETEXT

Ch. 4.1 - Prob. 1P Ch. 4.1 - Prob. 2P Ch. 4.1 - Prob. 3P Ch. 4.1 - Prob. 4P Ch. 4.1 - Prob. 5P Ch. 4.1 - Prob. 6P Ch. 4.1 - Prob. 7P Ch. 4.1 - Prob. 8P Ch. 4.1 - Prob. 9P Ch. 4.1 - Prob. 10P

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(a) To calculate: The maximum and minimum values of blood pressure.

Solution Summary: The author calculates the maximum and minimum blood pressures in millimetres of mercury, and the time between successive maxima.

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(a) To calculate: The maximum and minimum values of blood pressure.

(b) To calculate: The time between successive maxima.

(c) To graph: The blood pressure against time.

Want to see the full answer?

Chapter 4 Solutions

(a)

To calculate:

The maximum and minimum values of blood pressure.

(b)

To calculate:

The time between successive maxima.

(c)

To graph:

The blood pressure against time.