I need help with this question.
Find the equation of a line passing through point (3,-2) and perpendicular to the line 2x + 3y + 4-0.
Expert Answer
To find slope of the given line, we express it in a standard form, y = mx + c, we get:
Comparing the equation obtained above with the standard form, we get:
If m1 and m2 are the slopes of two lines that are perpendicular to each other, then we have, m1* m2 = -1. Here, let m1 be the slope obtained above, then m1 = -2/3. Solving for m2, we get:
Hence, we get slope of the line, for which we have to find the equation, as m2 = 3/2. Now, we have the slope of the line and a point through which line is passing. The equation of line is then given as:
Here, we have, m = 3/2 and (x1,y1) = (3,-2). Plugging the values in the above equation, we get:
Answer: The required equation of line is:
