S sunny = { D1,D2,D8,D9,D11 } Gain ( S sunny, Humidity) = 0.970 - (3/5)0.0 - (2/5) 0.0 = 0.970 Gain (S sunny, Temperature ) = 0.970 - (2/5) 0.0 - (2/5) 1.0 - (1/5) 0.0 = 0.570 Gain ( S sunny, wind ) = 0.970 - (2/5) 1.0 - (3/5) 0.190 Java. tree, Code import java.util.ArrayList; public class Entropy { public static double calculateEntropy(ArrayList data) { double entropy = 0; if(data.size() == 0) { // nothing to do return 0; } for(int i = 0; i < Hw1.setSize("PlayTennis"); i++) { int count = 0; for(int j = 0; j < data.size(); j++) { Record record = data.get(j); if(record.getAttributes().get(4).getValue() == i) { count++; } } double probability = count / (double)data.size(); if(count > 0) { entropy += -probability * (Math.log(probability) / Math.log(2)); } } return entropy; } public static double calculateGain(double rootEntropy, ArrayList subEntropies, ArrayList setSizes, int data) { double gain = rootEntropy; for(int i = 0; i < subEntropies.size(); i++) { gain += -((setSizes.get(i) / (double)data) * subEntropies.get(i)); } return gain; } } Gain calculation please refer to the above formula import java.io.*; import java.util.*; public class Tree { public Node buildTree(ArrayList records, Node root, LearningSet learningSet) { int bestAttribute = -1; double bestGain = 0; root.setEntropy(Entropy.calculateEntropy(root.getData())); if(root.getEntropy() == 0) {
Finally we got all our number and determine the slope, and the intercept in order to find out the forecast for the next
Submission: The report from part 4 including all relevant graphs and numerical analysis along with interpretations.
SQRT(2 * F * T / H) = (2 * 80 * 200,000 / 1.00)0.5
Complete the calculations below using this data. Show all of your work and clearly label each of your calculations.
The equation should look like: Range = 2 * 20 * 10^-6 * 4 * 10^-6 which is =
Provide detailed descriptions and show all calculations used to arrive at solutions for the following questions:
Use Equation v2= (r/m)Fc [1] and [4] to solve for T. From this equation, determine what should happen to T as Fc is increased. Circle it on Data Sheet A.
4) Using the new values of am recalculate the new values for bm . (1)
I am unable to answer this question because I don’t think I have enough information. This is asking for exact values and I don’t have the data to answer it. I maybe overlooking the answer but I am unable to figure this out.
Before we examine and try and solve this problem, here is some background information to get you
The receiving overhead per unit of Pumps produced = (0.19 X 20,000)/ 12500 = $0.3
The line of best-fit is used to find the gradient, the T2/L value, if straight or linear it shows that the relationship between the two is directly proportional. Using the original equation, you can square both sides and rearrange it to make . Then you can input the gradient value (T2/L) and work out g. , where g equals 10.13 m/s2. This value is close to the
= IRR (normal) * 0.7 + IRR (best) * 0.2 + IRR (worst) * 0.1
Variable Cost per Unit = ( $59,000 − $38,000 ) ÷ ( 3,000 − 1,250 ) = $12 per unit
The receiving overhead per unit of Pumps produced = (0.19 X 20,000)/ 12500 = $0.3