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Frequency Distribution & Graphic Presentation

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ASSIGNMENT ON FREQUENCY DISTRIBUTION & GRAPHIC PRESENTATION ( EX. # 32 & 30 ) SUBMITTED TO: FARZANA LALARUKH DEPT. OF FINANCE UNIVERSITY OF DHAKA SUBMITTED BY: SHEAKH MOHAMMAD KHALED MAHTAB ID# 11046 DEPT. OF FINANCE EMBA UNIVERSITY OF DHAKA Date of submission: February 27, 2007 Exercise # 32 The Midland National Bank selected a sample of 40 student checking accounts. Below are their end-of-the-month balances: 404 87 703 968 74 234 125 712 234 68 350 503 149 489 440 489 279 57 37 327 215 185 252 608 123 141 27 358 55 758 521 425 43 72 302 303 321 863 127 203 a) Tally the data into a frequency distribution using $100 as a class interval and $0 as the starting point. b) Draw a cumulative …show more content…

Now, we draw a virticle line from 400 on the X-axis to the polygon. Next, we draw a horizontal line to the percentage scale, which intersect it at 67.5%. Therefore, the percentage of the preferred customers is (100-67.5)% or 32.5%. (d) To find the cutoff point, first we draw a horizontal line from 10% of the percentage table to the polygon. Then drop down to the X-axis and read the cutoff point. Therefore, the cutoff point is 33. Page 3 of 6 Percentage of studedents Nurber 35 600, 34 700, 35 90 32.5% 0 90 more preferred customer 40 1000, 40 100 900, 39 Solution # 30 The number of shareholders of the selectedgroup of large companies(in thousands) are as below. 144 177 266 133 209 264 160 143 246 151 239 204 204 195 176 175 200 173 195 220 251 137 150 252 158 162 165 223 158 162 225 161 (a) Number of observation,N = Highest Value, H.V. = Lowest Value, L.V. = Number of Classes (K) => Class Interval (i) i ≥ => i ≥ 2 k k 32 266 133 ≥ = 32 7 H.V. - L.V. K 266 -133 7 20 H+L 2 => i= Class Mid Point = Higher Limit - Lower Limit 2 = SL.No. 1 2 3 4 5 6 7 Class Interval 130 130 150 170 190 210 230 250 Total= 150 170 190 210 230 250 270 Class 120 140

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