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Magnesium Reaction

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Magnesium reaction with Oxygen under the high temperature

Introduction

The aim of the experiment is to observe how Magnesium reacts with the Oxygen under the high temperature and to calculate percentage yield of the product.

Magnesium (solid) + Oxygen (gas) ⟶ Magnesium Oxide (solid)

2Mg (s) + O_2(g) ⟶ 2MgO (s)

Results

Crucible with the lid on was weighted, mass 1 – 18.43g.
Magnesium inside the crucible with the lid on was weighted, mass 2 – 19.09g.

Crucible with the lid on, containing Magnesium, was placed on the pipe clay triangle. Bunsen burner was lighted with gentle blue flame, later increased to a roaring flame (with the air hole fully opened) to get reaction going. Soon the crucible heated up, the lid was lifted gently …show more content…

If 48g of Mg produces 80g of MgO, than 1g of Mg produces: (80.6 g)/(48.6 g) = 1.66g of MgO.

So if started with 0.66g of Mg, this means 0.66g x 1.66g = 1.0956g of MgO should have been received. (Theoretical yield)

Percentage yield of MgO = (1.01 g)/(1.0956 g) x 100% = 92.18 %

The percentage yield of the product is quite high, this shows that experiment was 92.18% accurate.

This reaction caused a chemical change. When Magnesium reacted with Oxygen new compound was formed called Magnesium Oxide. Magnesium Oxide was solid, it changed the color to white/grey as well as increased in weight by 0.35g. Magnesium and Oxygen bonds where broken in order to compose another new compound. Magnesium being a metal, positively charged, had 2 electrons to give away, and Oxygen being nonmetal, negatively charged, had 2 spaces for the electrons to join. So the bond between these two elements is ionic bond, which made Magnesium Oxide really strong compound, because both elements are oppositely charged ions. This is why it would be really difficult to pull them apart, as well as the melting point is really

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