Chemistry Lab Report example:
Chemistry Laboratory Report (Magnesium Oxide)
INTRODUCTION:
As we learned before on how to determine the empirical formula of a compound based on the test and also chemical analysis on it. Hence this experiment is mainly goes around with how to determine the empirical formula of Magnesium Oxide following various tight procedures in order to get the knowledge and apply it onto another compounds. We are investigating the empirical formula of Magnesium Oxide in this experiment.
RESEARCH QUESTION:
How empirical formula of Magnesium Oxide is obtained by heating Magnesium in the presence of air?
HYPOTHESIS:
When Magnesium and Oxygen are heated together, they readily undergo a chemical change
Magnesium +
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The ribbon is not. The crucible is heated for another 10 minutes. Step 9 is repeated until the ribbon become whitish. Then the crucible is allowed to cool.
10. The crucible and the end product is weighed.
DATA TABLE:
Items
Mass(+/- 0.001)g
Mass of crucible + lid
21.880
Mass of crucible + lid + magnesium
22.190
Mass of crucible + lid + magnesium oxide
22.380
Mass of magnesium oxide
0.500
Mass of magnesium
0.310
Mass of oxygen
0.190
DATA PROCESSING:
Mass of magnesium used
= 22.190g – 21.880g
= 0.310g
Moles of magnesium
=0.310g/24.310 g mol -1
=0.01275 mol
Mass of oxygen that combines with magnesium
= 22.380g – 22.190g
= 0.190g
Moles of oxygen
= 0.190g/16.000g mol -1
= 0.011875 mol
Empirical formula
Magnesium (Mg)
Oxygen (O)
Mass
0.310g
0.190g
Mole
=0.310g/24.310g mol -1
=0.012752 mol
=0.190g/16.000g mol -1
=0.011875 mol
Ratio
= 0.012752mol/0.011875mol
=1.1
=1
=0.011875mol /0.011875mol
= 1
Formula
MgO
MgO
Experimental percent oxygen in Magnesium Oxide
Mass of MgO = 0.190g
=0.190g/0.500g x 100
=38%
Experimental percent magnesium in Magnesium Oxide
Mass of magnesium= 0.310g
=0.310g/0.500g x 100
= 62%
Theoretical percent oxygen in Magnesium Oxide
Formula: 2Mg + O2 → 2MgO
Moles of MgO = 0.500g/(24.310+16.000)g mol -1
= 0.01240387 mol
From the equation:
2 mol of MgO→1 mol of O2
0.01240387 mol→0.006219 mol
Mass = 0.062019g x 32 g mol -1
= 0.1984000g
Percent =
2. When the magnesium ignited, removed it from the flame and held it over an evaporating dish or a pyrex watch glass until the metal had burned completely. Let the product fall into the evaporating dish.
Empirical formulas represent the ratio of atoms in a formula. It is expressed in the simplest, small, whole number ratio. The molecular formula can either be the empirical formula, or a multiple of the empirical
2. The second source of error in the lab is when opening the lid of the crucible which allowed smoke of magnesium oxide to escape. During the lab, we removed the lid a couple of times to allow oxygen to enter the crucible so the magnesium reacts with the air to form magnesium oxide. However, the smoke could have easily escaped from the crucible because of the strong force of heat from the laboratory burner. This could have affected the lab results by decreasing the final mass when some of the product have escaped.
As a group, we obtained our salt mixture of calcium chloride and potassium oxalate, and weighed the mixture. We were able to make an aqueous solution from the mixture and distilled water. We boiled and filtered off the solution, leaving the precipitate. Once the precipitate was dried overnight, it was weighed and the mass was measured. Then we calculated the moles of the precipitate.
Materials:Magnesium stripCrucibleCrucible coverClay triangleIron ringRetort standTongsBalanceBunsen burnerProcedure:1.obtained a strip of magnesium between 30-40 cm long2.coiled magnesium strip into a tight roll3.measured the mass of the crucible and cover4.Added the magnesium strip to the crucible and measured the
The first experiment is about the combustion of magnesium after which the ash is formed.
The purpose of this lab was to test the law of definite proportions for the synthesis reaction of combusting magnesium. In this lab, the polished magnesium ribbon was placed in covered crucible and was heated in order for it to react with Oxygen presented in air and in water provided. The result showed that Magnesium oxide formed through chemical reaction was made up of 60.19% magnesium and 39.81% oxygen, which is approximate proportion of both particles in every Magnesium oxide compound. From this lab it can be concluded that the law of definite proportion stating that the elements in a pure compound combine in definite proportion to each other is factual.
The primary goal of this laboratory is to correctly identify an unknown substance. To achieve this task, one may use various tests that reveal both chemical and physical properties of a substance. By comparing the results of a known substance and the unknown substance, one may eliminate alternative possibilities and more accurately predict the undisclosed compound. Furthermore, by performing these tests, data can be collected and verified regarding chemical and physical properties of the unknown. Understanding the chemical properties of a known substance aids one’s understanding of the unknown based on comparative analysis of the results of the tests.
In this lab, a calorimeter was used to find the enthalpy of reaction for two reactions, the first was between magnesium and 1 molar hydrochloric acid, and the second was between magnesium oxide and 1 molar hydrochloric acid. After the enthalpy for both of these were found, Hess’ law was used to find the molar enthalpy of combustion of magnesium, using the enthalpies for the two previous reactions and the enthalpy of formation for water. The enthalpy of reaction for the magnesium + hydrochloric acid reaction was found to be -812.76 kJ. The enthalpy of reaction for the magnesium oxide + hydrochloric acid reaction was found to be -111.06 kJ. These two enthalpies and the enthalpy of formation for water were manipulated and added together using Hess’s law to get the molar enthalpy of combustion of magnesium. It was found that the molar enthalpy of combustion of magnesium was -987.5 kJ/mol. The accepted enthalpy was -601.6 kJ/mol, which means that there is a percent difference of 64%. This percent difference is very high which indicates that this type of experiment is very inefficient for finding the molar enthalpy of combustion of magnesium. Most likely, a there are many errors in this simple calorimeter experiment that make it inefficient for finding the molar enthalpy of combustion of magnesium.
Magnesium ribbon was reacted with Hydrochloric acid in three different experiments to determine the charge on a metal ion. After running multiple tests in the three different procedures, the Crystallization method proved to be the best method for determining the charge of the metal ion by using mole to mole ratio.
There is a very easy way to find the empirical formula of a compound using the mass percentages found through elemental analysis. First, convert the mass percentages to a mass, assuming that the compound is 100g. Then convert each mass into moles using the molar masses. Then divide each of these moles by the element with the smallest amount of moles. That is the ratio of the empirical formula. Just make sure that the numbers are in whole numbers, if not, multiply by common denominators to get all of them to a whole number (3).
A1.Work under the hood! With a pair of tongs, hold a strip of magnesium in a bunsen burner flame. Do not look directly at the flame. Save the ash in a small beaker for the next procedure. If magnesium is substance "A" in the general equation, what is "B"?
The goal of this experiment was to determine the empirical formula for a hydrate of magnesium sulfate and water. The technique that was used was measure the mass of the hydrate and then apply heat to evaporate the water. Then determine the mass of water that was in the hydrate and the mass of the remaining magnesium sulfate. The equation for the hydrate is determined by calculating the mole to mole ratio of the water and the anhydrous. The resulting formula will be formated as: MgSO4*_H2O
The powdered cobalt oxalate hydrate was weighed to about 0.3 g and placed in a pre-weighed crucible. The crucible and the cobalt oxalate were then heated until the cobalt oxalate decomposed into a stable, black solid, or Co3O4. Once the crucible was sufficiently
7. When the crucible cooled down so that one was able to hold it, the