. (бх + у?)dx + у(2х — Зу)dy %3D 0 . (2ху — tan y) dx + (x? — xsec'y)dy -о

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Q: If y = tan-1 xy and (x = 2, y = 3) y will be equal to?

A: See the attachment

Q: cos z) dz 4 5.

A: Given: - The indefinite integral is, ∫e2zcos14zdz To find: - The solution of the given integral.

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Q: 2-x 4x + 4x - -m(4x* + 4x – 3) + In| (2x 2x- – 3 x +1 x(x + 3)(x + 2)(x – 1) 1 (x + 3)*(x – 1)ª I…

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Q: Solve Variation of parameters to find y. and Yp and y y" + y = secxtanx

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Q: 2 iii. sech x3 tanh( x3 S- -dx 1 X3

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Q: 5-(1+x')(dy-dx)= 2.xydx;

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Q: Evaluate the integrals

A: Given I=∫01∫03-3x∫03-3x-y1dzdydx

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Q: (a) (Ex) ((Ax --> Bd) --> Ky) (b) (Ex) ~ (Dx v Cy) (c) -(x) (Dy --> (Hx v ~Ga))

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Q: 2. [2x*tan y – ysin (2) – 1] dx + [xsin (2) + x*sec*y] dy =

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Q: 7,9,-4) y dx +x dy +3 dz = (5,4,1)

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Q: 4. sin Tx - y = 0 4 -- y = -1 5.

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Q: 1. (3x – 2y + 1)dx + (3x – 2y + 3)dy = ( -

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Q: (2(1-2) (1--) dy dx dz 1-z) Evaluate S, a-2 (1-

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Q: Evalute! 2. 2)dy dx

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Q: find dy/dx

A: y=∫sec x21t2+1dt.

Q: (÷) – -, y (1) = 1 y tan-! y'= '() x tan-!

A: We will find out the required solution.

Q: Apply variation of parameters to find a particular solution of y ''' - y' = tan x

A: The given differential equation is y''-y' = tan x.We have to solve this using the variation of…

Q: 2. 2y+ly-1 dy

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Q: 7. 2r tan y dx + sec² y dy = 0

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Q: (2,5, – 6) | 16x dx + 4y dy + 2z dz (0,0,0)

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Q: 10-4z .5-2x-y 6z2 dz dy dx

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Q: 3z cos(z)dz

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Q: 23. cos (3z + 4) dz 25. sec2 (3x + 2) dx

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Q: 1 ,-(x-a)/b dx a

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Q: 1 -dx= cosº x/2sinx 5 /tanx+=Vtanº x + C А. Vtanx+/tan5x+C 1 B. tanx +÷Vtan° x +C С. 2 2 tan x +C 1…

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Q: 14-2x 1. ! ] dydx 0 2 2. dxdy 0 y 11-r 3. dycx o 1-x 4. [[ dydx 0 0

A: Answer 1: changing dy dx to dx dy; limits of integration: 0 ≤ x ≤  [2 - (y/2)] 2 ≤ y ≤ 4

Q: dx 2х — 7у dt dy 5х + 10у + 4z dt dz 5у + 2z dt

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Q: If y = tan-1 xy and (x = 2, y = 3) %3D %3D y will be equal to?

A: Given: y=tan-1xy To find y' at x=2 and y=3. Solution: Chain rule of differentiation states that:…

Q: 4. STT- COs y dy -COS

A: The objective of the question is evaluate the indefinite integral.

Q: dy 2 = 3, ,3 X'y' - xy dx

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Q: х2 9 dy + sinx - у %3D0 dx

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Q: Geberal solution of (3xy +3y - 4)dx+(x+1)²dy

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Q: 3z (sec-(-3z?))³ 2|–3z*|-/9zª–1 If y= sec-1 (-3x²), then dy dz

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Q: sec zdz

A: ∫03π4sec6zdz

Q: 2. (9y-2 +6y-4-y-5+1) dy 3. √ (12x²-x²+x²) dx

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Q: 7. dx * = + 2 dy Lal

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Q: Find dy/dx if sin-(4y²) = 8x² – 5y3 Answer: Find dy/dx if tan- (xy²) = 3x² – 5y² Answer:

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Q: 2-S S dx dy

A: to find the double integral we consider a strip parallel to x axis

Q: 1- S 9-4x2 dx 2 - x tan- x dx

A: 1.Given integral,               ∫9-x2xdx

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Q: Determine the general solution of y" + y = tanx using variation of parameters

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Q: (1-xy)^(-2) dx + [y^2 +x^2(1-xy)^-2]dy=0; when x=4, y=1

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Q: 3 - 2 (6x + y) dx dy 0 -5

A: To find : double integration

Q: (2x–1)(cos(/3(2x–1)3+6)dx V3(2x-1)3+6

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