VI. Find the volume bounded by z = 9– x² – y and z = 0. Give a numericalanswer.

Answered: . Find the volume bounded by z = 9 –x²…

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter10: Analytic Geometry

Section10.1: The Rectangular Coordinate System

Problem 40E: Find the exact volume of the solid that results when the region bounded in quadrant I by the axes...

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VI. Find the volume bounded by z = 9– x² – y and z = 0. Give a numerical
answer.

Expert Solution

Step 1

Given that the region is bounded by $z = 9 - x^{2} - y^{2}$ and $z = 0$ .

We know that the volume bounded between $z = f (x, y)$ and $z = g (x, y)$ over the region R is given by $\iint_{R} (f (x, y) - g (x, y)) d x d y$ where R is the projection on to the $x y$ plane.

Here, we have $z = f (x, y)$ as $z = 9 - x^{2} - y^{2}$ and $z = g (x, y)$ as $z = 0$ .

Hence, the volume is given by $V o l u m e = \iint_{R} (9 - x^{2} - y^{2}) d x d y$ where R is the region obtained by solving $z = 9 - x^{2} - y^{2}$ and $z = 0$ .

When $z = 0$ , we get

$z = 9 - x^{2} - y^{2} \Rightarrow 0 = 9 - x^{2} - y^{2} \Rightarrow x^{2} + y^{2} = 9$

Note that, $x^{2} + y^{2} = 9$ represents a circle of radius 3 with center at the origin.

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