. The distance between points C and D is 555'. If the temperature of the steel tape while measuring distance C to D is 34 degree Celsius, what is the correct distance?
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- A student used a 30m tape in measuring inclined distance. The measured length on the slope was recorded to be 459.20m long. The difference in elevation between the initial point and end point was found out to be 1.25m. The tape is of standard at a temperature of 10°C and a pull of 50N. During measurement the temperature reading was 15°C and the tape was supported at both ends with an applied pull of 75N. The cross-sectional area of the tape is 6.5mm? and the modulus of elasticity is 200GPA. The tape has a mass of 0.075 kg/m. K = 0.0000116 Determine the following: a. Total temperature correction b. Total pull correction Total sag correction С. d. Slope correction е. Corrected horizontal line3.A civil engineer used a 30m tape in measuring an inclined distance. The measured length on the slope was recorded to be 459.20 m long. The difference in elevation between the initial point and the end point was found to be 1.25m. The 30m tape is of standard length at a temperature of 10°C and a pull of 50 N. During measurement the temperature reading was 15°C and the tape was supported at both ends with an applied pull of 75 N. The cross-sectional area of the tape is 6.50 sq. mm and the modulus of elasticity is 200GPa. The tape has a mass of 0.075 kg/m. a. determine the total correction per tape length. b. determine the correction for slope. c. determine the horizontal distance.How was this 0.68 V2 calculated? And also 40.77 f V2 because I am not getting that..
- A 20 m tape was used for measuring a line at an average temperature of 65º F. The measured distances on the ground and slope of the ground are as given below: 2º 18′ for 125 m 3º 30′ for 250 m 1º 42′ for a distance of 170 m If the temperature at which tape was standardised is 80º F, find the true length of the line. Take α = 6.2 × 10^(–6) /ºF.What must be the pull in a (7)(10) meters tape in order to eliminate the sag and temperature correction, given the following? a = 7x10% m? E = 2x101 N/m? Weight of tape, 11 N Po = 10kg To = 22°C T = 20°C K= 0.0000116/°C The tape length is supported at both ends. Fundamentals of surveyingWhat must be the pull in a 70 meters tape in order to eliminate the sag and temperature correction, given the following? a = 7x10^-6m? E = 2x10^11N/m? Weight of tape, 11 N Po = 10kg To = 22°C T = 20°C K= 0.0000116/°C The tape length is supported at both ends.
- An angle APB is measured at different times using various instruments and procedures. The results, which are assigned certain weights, are as follows: 46-13-28, wt 1; 46-13-32, wt 2; 43-13-30, wt 3; and 43-13-32 , wt 4. What is the most probable value of the angle?Solve and show compleete solution.A theodolite is set up at point A and a subtense bar mounted on a tripod set up on point B. The instrument sighted the leftmost end of the subtense bar and the initial reading is 0°15’14”. The surveyor turned the theodolite clockwise and sighted the rightmost end of the subtense bar and the final reading is 1°51’05”. What is the distance between point A and B?. (The angle between 2 lines is the difference of the final and initial reading)Compute the vertical distance based on the following conditions: Sta occupied :T1 ;Sta observed :T2 ; Elevation of T1= 81.46m ;HI =Height of telescope above station mark =1.62 m;Point sighted on rod =HI= 1.62m;Vertical Angle =+4deg 38 min ;stadia interval =0.94 m ;f/i= 100; Stadia constant=0.30 Note: Pls show your complete solution
- What must be the pull in a 70 meters tape in order to eliminate the sag and temperature correction, given the following? a = 7x10% m? E = 2x101 N/m? Weight of tape, 11 N Po = 10kg To = 22°C T = 20°C K= 0.0000116/°C The tape length is supported at both ends.A distance measured with a 50m steel tape is recorded as 696.41m. The tape is known to be 0.015 m too long. What is the correct length of the line in meters? A. 696.201 C. 696.873 B. 696.619 D. 696.345 A 30-m steel tape is 2 mm too long at 20 °C. A rectangular lot was measured with the use of this tape. The sides are recorded as 144.95 m and 113.00 m. The average temperature during the measurement is 30 °C. Use coefficient of expansion of steel tape 0.0000116 m/m °C. What is the true area of the rectangular lot, in ?2? A. 16,835.55 C. 16,538.88 B. 16,385.33 D. 16,238.22 A distance between points A and B is measured and recorded as 123.456 meters using a tape that has a certified length of 29.992 meters. What is the true distance between A and B? A. 123.468 m C. 123.489 m B. 123.448 m D. 123.423 m ps. with solution, please.Give me both right answer with explanation. Which of the following would produce the greatest error when taping a distance of 100' with a steel tape? a. the tape is supported throughout but pulled with too litte tension b the tape is 2' off line c the tape is supported throughtout but pulled with too much tension d. the tape is on a 5% slope without correcting for it After a day of field work, you should copy and/or rewrite you field notes to make them nearer and more readable. True False