. Two wooden planks, each 20 mm thick and 160 mm wide, are joined by the glued mortise joint shown. Knowing that the joint will fail when the average shearing stress in the glue reaches 820 kPa and is to withstand an external load of magnitude P = 8 kN, determine the smallest allowable length d of the cuts of the joint 20 mm |-| KUNN Clue 160 mm 20 mm

. Two wooden planks, each 20 mm thick and 160 mm wide, are joined by the glued mortise joint shown. Knowing that the joint will fail when the average shearing stress in the glue reaches 820 kPa and is to withstand an external load of magnitude P = 8 kN, determine the smallest allowable length d of the cuts of the joint 20 mm |-| KUNN Clue 160 mm 20 mm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The beam is constructed from three boards. (Figure 1) The allowable shear stress for the wood is τallow=465 psiτallow=465 psi. Each nail can resist a shear force of 395 lblb. -Determine the maximum loads P that it can support. -What is the maximum allowable spacing ss of the nails used to hold the top flange to the web? (Consider only regions AC and BD.) -What is the maximum allowable spacing ss of the nails used to hold the bottom flange to the web? (Consider only regions AC and BD.)
Two wood boards, each 18 mm thick, are joined by the glued finger joint shown. The finger joint will fail when the average shear stress in the glue reaches 1090 kPa. Determine the shortest allowable length d of the cuts if the joint is to withstand an axial load of P = 3.9 kN. Use a = 23 mm and b = 184 mm.
The piece of wood, 100 mm by 100 mm in cross section, contains a glued joint inclined at the angle y to the vertical. The working stresses are 20 MPa for wood in tension, 8 MPa for glue in tension, and 12 MPa for glue in shear. If y ¼ 50 , determine the largest allowable axial force P.Show FBD of the three stresses
The beam is constructed from three boards. Determine the maximum shear V that it can support if the allowable shear stress for the wood is tallow = 400 psi. What is the maximum allowable spacing s of the nails if each nail can resist a shear force of 400 lb?
Pls help. A laminated wood beam consists of eight 2 in. × 7.00-in. planks glued together to form a section b = 7.00 in. wide by d = 16 in. deep, as shown. If the allowable strength of the glue in shear is 135 psi, determine (a) the maximum uniformly distributed load w that can be applied over the full length of the beam if the beam is simply supported and has a span of L = 21 ft. (b) the shear stress in the glue joint at H, which is located 4 in. above the bottom of the beam and at a distance of x = 76 in. from the left support. Assume that the beam is subjected to the load w determined in part (a). (c) the maximum tension bending stress in the beam when the load of part (a) is applied.
It is obtained by fixing 4 wooden planks to each other with nails.given as a cross section. 2 verticals forming the sectionplank 20 mm X 80 mm, the other two planks 20 mm X 120 mmin size. between the nails fastening the planksthe distance is s = 50 mm. allowed on each nailThe safe cutting force is 300 N. a) What is the highest vertical shear force that the beam can safely carry? b) What is the highest shear stress occurring in the section corresponding to this shear force?
If the allowable shear strength of the wood is 80 psi, determine the maximum load P that may be applied at midspan.
The two pieces of wood, 2.94in. by 4.76 in., are glued together along the 48ᴼjoint. Determine the maximum safe axial load P (in lb) that can be applied if the shear stress in the glue is limited to 275 psi. Round off the final answer to three decimal places.
A wooden beam is fabricated from one 2 × 16 and two 2 × 10 dimension lumber boards to form the double-tee cross-section shown. The beam flange is fastened to the stem with nails. Each nail can safely transmit a force of 176 lb in direct shear. The allowable shear stress of the wood is 83 psi. Assume b1 = 16 in., b2 = 2 in., d1 = 2 in., d2 = 10 in.(b) What nail spacing s would be necessary to develop the full strength of the double-tee shape in shear? (Full strength means that the maximum horizontal shear stress in the double-tee shape equals the allowable shear stress of the wood.) [Answer: s = 1.17 in]
A 16 ??–diameter steel rod AB is fitted to a round hole near end C of the wooden member CD. For the loading shown, determine, (a) the distance b for which the average shearing stress is 7??? on the surfaces indicated by the dashed lines, (provide FBD and answer in ??)(b) the average bearing stress on the wood (provide FBD and answer in ???)
A laminated wood beam consists of eight 2.25 in. × 5.00-in. planks glued together to form a section b = 5.00 in. wide by d = 18 in. deep, as shown and w = 663.2 lb/ft. If the allowable strength of the glue in shear is 105 psi, Determine:(b) the shear stress in the glue joint at H, which is located 4.5 in. above the bottom of the beam and at a distance of x = 86 in. from the left support. Assume that the beam is subjected to the load w determined in part (a). [Answer: τH = 19.34 psi]
Number of full joints (J1)?