.2 2! +... 4! 6!

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 47RE
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Question

Use the table in the picture to help you find a Function with the indicated series representation.

Table 11.5
1
=1 + x + x² + . ..+x* +
r*, for |x| < 1
1
Iso
= 1 – x + x² –..+ (-1)*x* -
1 + x
+ •
(-1)*x, for x| < 1
for |x| < 1
k=0
x²
e = 1 + x +
2!
for x< ∞
%3D
k!
k!
k=0
:).
(-1)*x2k+1
(2k + 1)!
(-1)*x²*+1
Σ
k=0 (2k + 1)!
it
sin x = x -
3!
for x < ∞
5!
(-1)* x24
x²
x*
k 2k
(-1)* x*
2k
00
cos x = 1
for |x| < 0
%3D
2!
4!
(2k)!
(2k)!
k=0
x²
In (1 + x) = x
(-1)*+1 xk
+ · .
3.
(-1)*+1k
for -1 < x < 1
k
k=1
3.
-In (1 – x) = x +
2, for -1 sx< 1
+ .
3
k=1
k 2k+1
(-1)*x2k+1
(-1)* x²*+1
-1
tan'x = x
Σ
2k + 1
for x < 1
%3D
3
2k + 1
k=0
5.
2k+1
x2k+1
sinh x = x+
3!
for x < ∞
5!
(2k+1)!
k=0(2k + 1)!'
2k
2k
x-
cosh x = 1+
2!
Σ
(2k)!"
for x < ∞
4!
(2k)!
*, for |x| < 1 and
p(p - 1)(p- 2) (p – k+ 1)
(0)
(1 + x)' =
%3D
k!
8.
8.
8.
8.
+.
+.
Transcribed Image Text:Table 11.5 1 =1 + x + x² + . ..+x* + r*, for |x| < 1 1 Iso = 1 – x + x² –..+ (-1)*x* - 1 + x + • (-1)*x, for x| < 1 for |x| < 1 k=0 x² e = 1 + x + 2! for x< ∞ %3D k! k! k=0 :). (-1)*x2k+1 (2k + 1)! (-1)*x²*+1 Σ k=0 (2k + 1)! it sin x = x - 3! for x < ∞ 5! (-1)* x24 x² x* k 2k (-1)* x* 2k 00 cos x = 1 for |x| < 0 %3D 2! 4! (2k)! (2k)! k=0 x² In (1 + x) = x (-1)*+1 xk + · . 3. (-1)*+1k for -1 < x < 1 k k=1 3. -In (1 – x) = x + 2, for -1 sx< 1 + . 3 k=1 k 2k+1 (-1)*x2k+1 (-1)* x²*+1 -1 tan'x = x Σ 2k + 1 for x < 1 %3D 3 2k + 1 k=0 5. 2k+1 x2k+1 sinh x = x+ 3! for x < ∞ 5! (2k+1)! k=0(2k + 1)!' 2k 2k x- cosh x = 1+ 2! Σ (2k)!" for x < ∞ 4! (2k)! *, for |x| < 1 and p(p - 1)(p- 2) (p – k+ 1) (0) (1 + x)' = %3D k! 8. 8. 8. 8. +. +.
.2
2!
+...
4! 6!
Transcribed Image Text:.2 2! +... 4! 6!
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