.Consider the bit stream 01101101. Draw the waveforms for following line codes. (i) (ii) Biphase Manchester coding Biphase Differential Manchester coding Polar PSEUDOTERNARY (iii)
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2.Consider the bit stream 01101101. Draw the waveforms for following line codes.
(i)
(ii)
Biphase Manchester coding
Biphase Differential Manchester coding
Polar PSEUDOTERNARY
(iii)
(iv)
Multilevel -8B6T
(v)
Multilevel-2B1Q
Assume that the signal level for the most recent preceding 0 bit (pseudoternary) has a negative voltage.
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- #45.! Consider the following bit stream-a. 00000000 b. 11111111 c. 01010101 d. 00110011 Draw the graph of the i. Manchester using each of the given data streams, assuming that the last signal level has been positive. From thegraphs, guess the bandwidth for this scheme using the average number of changes in the signal level... .a) Draw the graph of the NRZ-I, Manchester & differential Manchester using data stream01010101, assuming that the last signal level has been positiveFor the bit stream 01001110, sketch the waveforms for each of the codes. Assume that the signal level for the preceding bit for NRZI was high; the most recent preceding 1 bit (AMI) has a negative voltage; and the most recent preceding 0 bit (pseudo temary) has a negative voltage.
- Consider a convolutional code with k = 1, n = 3 and L = 3. The encoder generators aregiven by 91 = [110], 92 = [001] and 93 = [011].Assume the Viterbi algorithm is used for decoding at the receiver and considerthe received bit sequence at the input of the channel decoder being [10 0100110011].Answer the following questions.(a) What is the decoded information bit sequence? (b) What is the value of the cumulative metric (i.e., Hamming distance) of thefinal survivor path of the decoding process?(c) Draw the final survivor path of the trellis for the decoding process.Instruction for Part (c): An example of drawing a path in the trellis is shown below.Convert 1, 9, and 1 into 8-bit ASCII characters usingeven parity. Convert this 24-bits digital data into digital signal using the following linecoding schemes:a) Bipolar AMIb) Polar NRZ-Lc) Polar differential Manchesterd) 2B1Qe) MLT-3If the bitrate is 1911*100 what will be required average bandwidth in these schemes.Comment about the DC component and baseline wandering nature of these schemes.1. Draw the digital signal for data stream 11001011 by using the following digital encoding techniques: a. Differential Manchester b. NRZ-L c. NRZ-I d. Manchester e. RZ
- a. Compute for the data efficiency of transmitting if the data format is a General Synchronous Data Frame. b. For an asynchronous data transmission (wherein 1 byte of data is accompanied by a specific number of auxiliary bits), how many start and stop bits are there if the data efficiency in transmitting is ? The number of start bits is equal to the number of stop bits.Draw the graph of the NRZ-L, NRZ-I, Manchester scheme, differential Manchesterscheme using each of the following data streams,assuming that the last signa11evel has been positive. From the graphs, guess thebandwidth for this scheme using the average number of changes in the signal level.a. 00000000b. 11111111c. 01010101d. 001100115.Assume M = 1 1 0 1 02 and P = 1 1 02. Compute: a. The frame check sum (FCS).b. The transmitted frame.c. The received frame and check if there is any error in the data.
- Consider an IEEE-like format ( one sign bit, 4 exp bits and 4 frac bits. ) with four frac bits and four exp bits. (i) What is the smallest integer m not exactly representable? Compute its decimal value. (ii) Is m+1 representable? Show the bit pattern for m+1 in this representation. (iii) What is the machine epsilon of this representation?Suppose, BanglaLink has 4 voice channels, each of 60Mbps. They use synchronous TDM to multiplex these channels. If 3 characters at a time are multiplexed (3 characters in each output slot), Draw the first two output frames with arbitrary inputs.Q4: Draw the constellation diagram of 2*4 QAM signal then show the output amplitudes and phases of the signal when the following data stream are modulated 11001011111100100011 .