0 1 0 0 0 1 and X= 2/3 0 1/3 a. Show that XP = X. 3x3 1x3 [11:3/2] x [i] = [ (09 - 160 - 32 1/3 X - [(0+0+ 1) (1+0+0) (0+1+¾6)] = [1 1₂ ¾/2₂] = X b. Use the result in part (a) to show that X (P4 - 13) = 0, where 0 is the zero matrix. Since XP=X as concluded in (a), = xp-p² 10. Let P= Braid I <=(11 3/2). 3/₂(2x) ((1+1(0)+7/260)) ((60) + 1(1) + 2/2]
0 1 0 0 0 1 and X= 2/3 0 1/3 a. Show that XP = X. 3x3 1x3 [11:3/2] x [i] = [ (09 - 160 - 32 1/3 X - [(0+0+ 1) (1+0+0) (0+1+¾6)] = [1 1₂ ¾/2₂] = X b. Use the result in part (a) to show that X (P4 - 13) = 0, where 0 is the zero matrix. Since XP=X as concluded in (a), = xp-p² 10. Let P= Braid I <=(11 3/2). 3/₂(2x) ((1+1(0)+7/260)) ((60) + 1(1) + 2/2]
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section3.5: Complex Zeros And The Fundamental Theorem Of Algebra
Problem 3E: A polynomial of degree n I has exactly ____________________zero if a zero of multiplicity m is...
Related questions
Question
![0
1
0
0 0 1
and X=
2/3 0 1/3
a. Show that XP = X. 33
1x3
[1 1 ¾/2]
G 1 G
O
[{[ (0) + (60)+ 32 (²x)) ((1)+1(0) + ¾/2(0)}) ({(60)+1(0)+22(A)]
X
erb St
2/30/3
X
P
= [(0+0+ 1) (1+0+0) (0+1 + ¾6)]
= [₁ ₁₂_¾/₂]
12_3/2]
= X
b. Use the result in part (a) to show that X(P4-13) = 0, where 0 is the
zero matrix.
Since XP=X as concluded in (a),
= xp.p²
= Xp
10. Let P=
1 1 3/2 ).
144 021](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc18b1235-dc93-42cf-ae10-5b973d004ef3%2F4b9ad780-2ee7-4d8a-9ec0-144ebb14a15b%2Fg1phs7e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:0
1
0
0 0 1
and X=
2/3 0 1/3
a. Show that XP = X. 33
1x3
[1 1 ¾/2]
G 1 G
O
[{[ (0) + (60)+ 32 (²x)) ((1)+1(0) + ¾/2(0)}) ({(60)+1(0)+22(A)]
X
erb St
2/30/3
X
P
= [(0+0+ 1) (1+0+0) (0+1 + ¾6)]
= [₁ ₁₂_¾/₂]
12_3/2]
= X
b. Use the result in part (a) to show that X(P4-13) = 0, where 0 is the
zero matrix.
Since XP=X as concluded in (a),
= xp.p²
= Xp
10. Let P=
1 1 3/2 ).
144 021
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