= 0 Siny 54+3x dx dy 7712 (5xy+3x3 2 0 д 12 Smy dy 5ysing + 3 siny 2 dy 7712 3 sin2y = -5y cosy +5 smy 3 y. 8 7/2 = - 5y cosy + 5 siny + 3 y 3 sin 2y 4 8 0 = -5 I cos I II cos I + 5 sin+ 3хд 2 3 Sin 2 (2) m2(즐) 8 - (-5) -5x ox cos + 55100) + 10 ΧΟ 8 = 5+38 Ans
= 0 Siny 54+3x dx dy 7712 (5xy+3x3 2 0 д 12 Smy dy 5ysing + 3 siny 2 dy 7712 3 sin2y = -5y cosy +5 smy 3 y. 8 7/2 = - 5y cosy + 5 siny + 3 y 3 sin 2y 4 8 0 = -5 I cos I II cos I + 5 sin+ 3хд 2 3 Sin 2 (2) m2(즐) 8 - (-5) -5x ox cos + 55100) + 10 ΧΟ 8 = 5+38 Ans
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 75E
Question
How to get the part that I circled??? Please explain.
![=
0
Siny
54+3x dx dy
7712
(5xy+3x3
2
0
д
12
Smy
dy
5ysing + 3 siny
2
dy
7712
3 sin2y
=
-5y cosy +5 smy
3 y.
8
7/2
= - 5y cosy + 5 siny + 3 y
3 sin 2y
4
8
0
= -5 I cos I
II cos I
+
5 sin+
3хд
2
3 Sin 2 (2)
m2(즐)
8
-
(-5)
-5x ox cos + 55100) + 10
ΧΟ
8
=
5+38
Ans](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e53cf2c-4bf5-4ccd-bd0e-fb990a97eda5%2F9c85dcc0-9713-48bc-bf56-cb6c1b291bcc%2Fawucqhc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:=
0
Siny
54+3x dx dy
7712
(5xy+3x3
2
0
д
12
Smy
dy
5ysing + 3 siny
2
dy
7712
3 sin2y
=
-5y cosy +5 smy
3 y.
8
7/2
= - 5y cosy + 5 siny + 3 y
3 sin 2y
4
8
0
= -5 I cos I
II cos I
+
5 sin+
3хд
2
3 Sin 2 (2)
m2(즐)
8
-
(-5)
-5x ox cos + 55100) + 10
ΧΟ
8
=
5+38
Ans
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