0.018 S2, A 210 V, 489.39682539683 A and 530 rpm DC separately excited motor has Ra 2000 – 2N Rf = 164 N and Va = Vf = 210. It drives load whose torque is expressed as T and N is the speed of the motor in rpm. Answer the following questions. la • Find the armature current Ia when the speed is 360 rpm and Vf =210 V. If Ia Ra • Calculate the field voltage Vf when the speed is 830 rpm. Vf Rf Ea V

0.018 S2, A 210 V, 489.39682539683 A and 530 rpm DC separately excited motor has Ra 2000 – 2N Rf = 164 N and Va = Vf = 210. It drives load whose torque is expressed as T and N is the speed of the motor in rpm. Answer the following questions. la • Find the armature current Ia when the speed is 360 rpm and Vf =210 V. If Ia Ra • Calculate the field voltage Vf when the speed is 830 rpm. Vf Rf Ea V

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Consider a shunt DC motor with an armature resistance RA =0.2N and terminal voltage VT = 160 V. The motor rated speed is 1800 RPM. The total field resistance 240 Q. Assume No armature reaction in this machine. The variation of the armature terminal voltage as a function of the field current is measured under no-load conditions and shown below: IF (A) EA (V) 1.0 141 0.0 0.6 125 These values were taken at speed n= 1800 RPM 0.1 0.2 0.3 0.4 0.5 0.7 0.8 0.9 30 60 85 102 115 132 137 140 If the motor is driving a load at an armature current IA=60 A, its rotational speed is 1517 RPM, with rotational losses of 848 Watt. What torque is induced by this motor? Select one: O a. Induced Torque = 62 N.m O b. Induced Torque = 56 N.m O c. None O d. Induced Torque = 51 N.m.
The rated parameters of a separately excited DC motor are: U=420V; Ia=57,5A; Ra=0.1Ω and kgφ=0,4263 (V/rpm). Friction, ventilation and core losses of the motor is 600 W and can be considered as constant. a) Calculate the output power and torque of the motor at nominal operating condition. b) The motor drives a load having half of the rated torque at nominal speed. Calculate the armature current, induced voltage at armature windings and the power drawn from the supply. Ignore the power losses in the field circuit. May I ask for can you send the answer after being tottaly sure about the answer and can you give some little explanations for each step of your solution. Thanks in advance.
Consider a shunt DC motor with an armature resistance RA = 0.125 N and terminal voltage VT = 380 V. The motor rated speed is 1000 RPM and the rated armature current is 100 A. The total field resistance is 260 Ohms. 0.3 85 These values were taken at speed n=1000 RPM 0.1 0.2 0.4 IF (A) EA (V) 0.0 0.5 0.6 0.7 0.8 30 60 102 115 124 130 134 What is the starting armature current of this motor? Select one: O a. Starting Current = 4030 Amp O b. Starting Current = 3040 Amp O c. None O d. Starting Current = 2500 Amp
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A 35.2 HP, 250 V, 100 A, 1200 RPM, series DC motor with no armature reaction is considered in this problem. This motor has a series-field winding of 5 turns per pole. Its armature resistance in RA =0.05 ohm, and its series field resistance is Rs =0.05 ohm. The magnetizationcurve at 1200 RPM is given by the following table:
a shunt-wound motor runs at 600 r.p.m from a 230 V supply when taking a line current of 50 A. its armature and Field resistance are 0.4 ohms and 104.5 ohms respectively. Neglecting the effects of armature reaction and allowing 2 V brush drop, calculate (a) the no-load speed if the no-load line current is 5 A. (b) the resistance to be placed in armature circuit in order to reduce the speed to 500 r.p.m when motor is taking a line current of 50 A . (c) the percentage reduction in the flux per pole in order that the speed maybe 750 r.p.m when the armature is 30 A with no added resistance in the armature circuit.
The rated parameters of a separately excited DC motor are: U=420V; Ia=57,5A; Ra=0.1Ω and kgf=0,4263 (V/rpm). Friction, ventilation and core losses of the motor is 600 W and can be considered as constant. Calculate the output power and torque of the motor at nominal operating condition. The motor drives a load having half of the rated torque at nominal speed. Calculate the armature current, induced voltage at armature windings and the power drawn from the supply. Ignore the power losses in the field circuit.
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