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0.225(1-z) H(z)=: 1+0.39z² -0.16z Determine: a. Graphical location of Poles and Zeros in the z-plane. b. Unit step-response assuming initially relaxed system. c. zero-input response for v-1) = 1, v-2) = 1. 0other initial states are zero.

0.225(1-z) H(z)=: 1+0.39z² -0.16z Determine: a. Graphical location of Poles and Zeros in the z-plane. b. Unit step-response assuming initially relaxed system. c. zero-input response for v-1) = 1, v-2) = 1. 0other initial states are zero.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Consider the system described by the transfer function

0.225(1-z) 1+0.39z² –0.16z H(z)= Determine: a. Graphical location of Poles and Zeros in the z-plane. b. Unit step-response assuming initially relaxed system. c. zero-input response for y(-1) = 1, y(-2) = 1, other initial states are zero.
Transcribed Image Text:0.225(1-z) 1+0.39z² –0.16z H(z)= Determine: a. Graphical location of Poles and Zeros in the z-plane. b. Unit step-response assuming initially relaxed system. c. zero-input response for y(-1) = 1, y(-2) = 1, other initial states are zero.
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