Answered: 0.5 k/ft B, 2 k- Inc = 400 in C E 8 ft…

Engineering

Civil Engineering

0.5 k/ft B, 2 k- Inc = 400 in C E 8 ft ICE = 400 in 3 k- Ipc = 500 in 8 ft LAB = 600 in A D 24 ft 12 ft Prob. 12–18

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter8: Engineering Materials

Section: Chapter Questions

Problem 85CQ

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Question

Determine the moments at each joint of the frame, then draw the moment diagram for member BCE. Assume B, C, and E are fixed connected and A and D are pins E = 29(10³) ksi.

0.5 k/ft
B,
2 k-
Inc = 400 in C
E
8 ft
ICE = 400 in
3 k-
Ipc = 500 in
8 ft
LAB = 600 in
A
D
24 ft
12 ft
Prob. 12–18

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Step 1: Calculating the moment at each joint of Frame.

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Step 2: As per the table calculation for fixed end moment.

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Step 3: Moment Diagram.

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