052-8 -4 -1 -7 -5 [E = 3 7 8-7 [A] = -9 5 1 -3 %3D -3 -9 6 4 4 -8 2 9

Q: 14. ) -10 < 4t- 2 s 6

A:

Q: -1 10 7-4 3-6-8-9 G) = 9 5 3-7 [4] = %3D 6-3-5 5 -6 -9 -2 -5 8 10 4-4 G] + [A] = 00

A: see 2nd step.

Q: 29. 30. - 16 s + 10 1 31. s2 - s - 2 32. (s + a)(s + b)

A:

Q: 4+ 3- 2+ 1+ -$ -4 -3 -2 -1 -1+ 1 2/3 45 -2+ -3+ 4

A:

Q: -30 1) +6 30 -6 -30 3) +6 -30 4) -6 -30 5) -6 -18 6) +3 -40 7) - +5 36 8) 9 2)

A:

Q: -10 -7 -6 7 -8 -4 4 2 2 -9 1 9 5 6 3 -1 [A] = [D] = -5 3 -4 -3 7 8 -3 1 -8 -2 10 -1 -2 -7 -5 10 3[A]…

A: Explanation of the answer is as follows

Q: -2{-12/-3+2[2²-12-√100]-(3²)}

A: We want to solve the given basic mathematical operation problem.

Q: 1-5 + 2)(s² + 4).

A: By the help of partial fraction method and using table of Laplace transform we solve the given…

Q: 25) 3+ 11x= 80 26) 44 =-4m-8 )-7+-=-14 28) -11 + =-13 29) -18 = 11x-7 30) -56 =-10r + 4

A: Solution: According to our guideline we are supposed to answer only 3 question . Kindly re-post…

Q: -1 -2 -6 2 -5 -7 3 -3 [E] -8 -10 8 7 -4 3[E] =

A:

Q: -3 -3 4 -9 ol 0 1 21 -2 3 1 D = 6 9 - A =| 3 |-2 -2 110 3 [3 0 0 F = 0 6 0 lo o -4 5 5 2 -1 E = -4…

A:

Q: 2s² 2s - bs +5 (s-1)(s-2) (s- 25.4 (s+)(s-2)(s-3)

A:

Q: [1 -2 3 3 4 12 -1 -21

A: Given : Matrix  1  -2  3 3  0   4 2  -1  -2

Q: (0, 16) A 16 4 12- (F15, 8) 8- (15, 8) 4- 16-12-8 -4 4 12 16 4 H(-15, -9) 8 (15,-9)E -12- 16…

A: To find the square feets of floorboards, We Break the Area in combination of Equilateral triangle…

Q: 4 -5 4 0 -5 -1 1 В. С 4 -5 0 2 -2 0 1 4 1 -2 2 ЗВ - С %—

A: Solve the two matrices B and C, in the form of 3B-C.Multiply the scalar product 3 with a matrix B,

Q: 10- 6- 4- 4 2+ -86-4- 246 8 -2H 4+ -6. G

A: BC = Base of triangle ABC Length of BC= 4units

Q: 7 1 -4-8 -1-7 -10 2 [E [G -4 2 15 -10 4 -3 0 [E] + [G] =

A:

Q: (-8/5)(-15/32)

A: We have to find  (-8/5) (-15/32) = ? Then ,

Q: 3 s2+2s-15 2s+5 s2+2s-13 | 3 s2+2s-15 53+6s+9 (s-1)(s-2)(s+4) 52+2s-3

A: We have to find the inverse Laplace transformation .

Q: 2.Find р2-ЗР+10 (i) L-1 (P+5)(p²+81). p-9 (ii) L-1 (p+1)(p-3). (ii) L*| 9 (P+6)2+64

A: Given : to find the inverse Laplace transform

Q: -6 -8 -2 7 0-7 6-8 [D] = -5 7 [E = -4 9 %3D -3 -4 1 3 2 4 -6 8 3[D] – 2[E] =

A: Given,            D =-6-80-7-57-3-424  and E =-276-8-4913-68

Q: 40 -10 -25 7 7 -3 A = -10 15 12 and B -7 8 4 -25 12 30 3 -4

A: →Matrix multiplication is always done in row to column wise.→For transpose, interchange row and…

Q: 2-1 4s - 4 s² - 16/

A:

Q: 3.) +248 3s-16 s²-24s+69

A:

Q: 2 7s- 41S +84 ) FG)= (5-1) (s²-45+13)

A:

Q: 4-¹ {√ 5. L- -48 se (3s + 2)(s - 2)

A:

Q: (9) y-) 1아 1아 -10 10 -10 10 -10 -10 1아 1아 -10 10 -10 -10

A: Consider the given graph of f(x).

Q: 4 -10 -8 -6 -2 12 4 6. 10 -2 -4 -6 -8 -10 8. 8 2.

A: Concept: From the given graph we shall determine the place of intersection. The coordinates of the…

Q: -1 34 -30 10

A:

Q: 10 -10/-9 -8 -7 -6 -5 -3 -2 -1 5 10 -2 -3 -4 -6 -7 5 43 ㅜ

A:

Q: A. 1 2 3. 3 3. 4 В. y -5 10 4 -3 C. y 14 -10 4 11 -6 -3 2 4 5 75 6. 1. N 3.

A: To Determine: which one is function. Given: we have a image of questions Explanation: A Function is…

Q: 13. A = 1 -4 03 -2 -2 8-4 [1 -2 14. A = 0 3 1 -2 27 5,b= -6 7,b= 5 3 -7 -3 -5 9

A: Given  A=1-42035-28-4 and b=3-7-3 We construct b as a linear combination of columns of A Such that,…

Q: 12 -10 4 10 -4 -15 -70 8 -30 16 -13 -1 -72 5 0| 9 R

A: 12    = N-10 = O4      =V10    =E-4   =L-15 =C-70 =O

Q: 1 4. 1. L s+9 s- 5 20 1 7 2. s+3 5s-3 6s-5 3. 4s+7

A:

Q: 5/9(7-6x)-3/4(3-15x)=1/12(3x-5)-1/2

A: we have to solve

Q: 4s + 12 s2 + 8s + 10 4e -4t – 4te -4t 4e4 + 4te4t Option 3 Option 2 -4t 4e + 4te¬4t

A:

Q: 1 2. Find L-1 [ s2-8s+25

A:

Q: P(-1.45 < Z < +1.45) =?

A: Draw the normal curve that represents between z=-1.45 &amp; z=+1.45.

Q: 4 4 - 5 3 - - 5 -1 %D 5 -5 2 3 1 4.

A: Simply use the concept of matrix multiplication. Multiply and add each element of each raw to…

Q: 13. -4х+5у3 20 5-4-3 -2 -1 2 3 4 5

A: To draw graph of given equation -4x+5y=20    ....(1)

Q: 817 () (i) (iii) L-1 (iv) L') 4s s2-16. (vi) L-15 2 (s) (vii) L-1 2(s+1) Is2+2s+10J 4s-3 (viii) L-1…

A: Topic -  inverse laplace transform

Q: (8 – 4)e-3s s2 – 4s + 5 Determine L-1

A: The inverse laplace transform rule. If L-1Fs=ft then 1. L-1e-asFs=Ht-aft-a, Here, H(t) is Heaviside…

Q: 2/3<-4/5(x-3)<1

A: Apply mathematical cross multiplication rule to solve inequality

Q: 4-1 { 27. 9-1 2s - 4 (s² + s)(s² + 1))

A: Solution :

Q: -2 4 1 3 -4 2 1 -2 x 1 -13 8. -1 1

A:

Q: (-0.1)-금 (30)+ (150) f-0.1)= 2 3. (-0.1) 3(-0.1) -0.)(120)=683 6. 4

A: Here we have to go back to just previous step were we have function,…