1 -1 1 1 4 -4 3 6 2 -2 1 3

Q: 4+ 7 + 3- 2- 5+ 2 - 5+ 1 - 1 - 6 + 1- 2 -

A: In the given question we have to solve the given Ken Ken puzzle . Before the solution we have to…

Q: 1 1 -4 16. -2 8.

A: Let the given matrix be A=1-4-28. (a) Evaluate det (A-λI2) as follows.…

Q: 4 3 1 -1 -2 -3. -5 п/2 25 3п/2 2п

A:

Q: 4 3 2. -8 -7 -6 -5 -4 -3 -2 -1 0 1. -1

A:

Q: 1 -3 4. A =| 0 1 -4 ,b = 3 -5 -9 -9

A:

Q: (1. 2) (3.-2) (-1.-2) (4.-3)

A: Integral of a function from a to b= area of the function from x=a to x=b

Q: 1 8 3 у 2 -3 7 2

A:

Q: 3 2. -4 -3-2 -1 0 1 2 3 -1 1.

A: The graph of y=x shifted 2 units up and 1 unit left.

Q: Find the product

A: Given: 4-23012-101261-102

Q: 6 0 -1 -3 23*2 4 -3.0 2 4 -5 -13х2

A: As per the question we are given an expression consisting of two 3×2 matrices and their linear…

Q: х -1 2 1 -1 х 2 1 = 0 х 1 |-1 2 -1 2 1

A:

Q: Compute the outer product expansion of AB.

A: Given matrices are

Q: 2 3 A=0-1 3 [1 -1 6] B-4 0 [4 3

A: Given matrices are We will find the product BA as follows.

Q: 2 -5 -4 -3 -2 -1 -3 -41 -5 3. 2. 3. 2:

A: First of all write the roots of given function:-x=-3,-3,0 are the rootsso factors will be

Q: 2х +3 Зх +4 5х -30 х- 6

A: Simplify

Q: 3 -1 2 -5 -2 01 -1 -2

A:

Q: )(- 2 3 1 2 3 7. -2 -2 3 -1 1 -1

A: Definition used -       Product of two matrices -         It is only possible when the number of…

Q: 4. 2 -2 1 0 23 -3-

A:

Q: 1 -1 1-1-2 1 3 2 1 1 1 -1 2 -2 2.

A:

Q: 1 1 -2 -4 A . 1 -4 and -4 4 A 1 A = ||

A: We have to solve given problem:

Q: 1 1 2 5 -5 1 -2 2 -3 5 -1 -1 2

A:

Q: 1 3 4 -3 -6 -7 3 3 -4 -5 -3 2] 2]

A:

Q: 4 3 -5 -4 -3-2 -1 1 2 3 4 3 2 3

A:

Q: 2 2 4 -2 3 3 6 -3 4 0 -4

A: We have to solve given problem:

Q: 1.0 1.0 -3 5

A:

Q: 4 3 -5 -4 -3 -2 -1 -1 1 2 3 4 5 -2 -3 -4 -5+

A:

Q: Verify that (AB)T = BTAT.

A:

Q: 2 1 -2 13. 1 3 3 2 4 -2

A:

Q: 3 -2 01 8. -6 B =|-6 A -2 3 7 -4 -4 3

A:

Q: 2. у 3 (3х — 1)°(х -5)° (4 — х)

A:

Q: (1.2) (3.-2) (-1.-2) (4.-3)

A: In the question it is asked to calculate the integral ∫-42f(x)dx for the graph given in question.

Q: 2х 5х+1 х2 - 2х-24 х2-7х+6 х2 +3х-4

A: Here we will perform the given operations,

Q: 2 -1 2 -3 1 2 1 -42, L -1 1 -3 1 -1 2

A:

Q: 1. [3 1 2] 2. [-1 2 -3] 3. [10 -5 2] 4. [-4 -5 -3]

A:

Q: 6. 1 [1 3 5) 4 -3 2 12 -4 -2 4.

A:

Q: 1 -4 4 0 - 1 3 -6 0 1 3 - 4 2 3 7

A:

Q: 6- 5 4 3 2 -6 -4 -3 -2 1 2 3 4 5 6 -1 -2 -3+ -4 -5-

A:

Q: 2 1 2 A = = | 3 -2 4 -3 -5]

A:

Q: 3 -4 2 11. -9 12 -6 -6 8 -4

A: We use the gauss-Jordan elimination method to solve a system of linear equations. First of all, we…

Q: -1 2 -3 1 2 1 C. -1 2 -3 1 1 6 -1

A:

Q: 4 1 0. 5 -3 -1 6- 4- 2. 2.

A: To find the solution by using cramer's rule

Q: Find AB.

A: Given: A=1234 -56, B=1-102-2310040-3 To find: AB

Q: a) 2 -3 1 -2 3 3 2 -1 4 b) 2 -6 3 1 3 -5 1 11

A: (a) 2-3321-23-154 =…

Q: 1 2 -3 -2 0 4 -1 -4 3 2 A = 2 4 1 -2 -2 3 4 -1 3

A: The given matrix is: A=   12-3   4-1-20-4   3   2   24   0   1-2-23   4-1   3

Q: 3. 2. -3-2 3. 5. -2 -3 -\

A: Area of triangle =12×b×h where h is height of triangle and b is length of base

Q: [1 2 3 -21 2-2 1 3. 3 3 0 4

A: Given matrix is: A=123-22-2133041