-1 1 2 A 3 3 4 det A 0 0 -2 0 0 2 4 B = -5 6. 1 5 3 3 det B: -1 0 0 0 3 0 0 C = 2 0 0 4 0 0 0 0 -2 det C =

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter5: Orthogonality
Section5.3: The Gram-schmidt Process And The Qr Factorization
Problem 11AEXP
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Question
-1
1
A
3
3
4
.2
det A
0 0]
4
-2 0 0
В
-5
6
1 0
5
3 3
det
В
1 0
0 0
3
0 0
C =
2 0
0 4
0 0 0
-2
det C =
2,
||
Transcribed Image Text:-1 1 A 3 3 4 .2 det A 0 0] 4 -2 0 0 В -5 6 1 0 5 3 3 det В 1 0 0 0 3 0 0 C = 2 0 0 4 0 0 0 -2 det C = 2, ||
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