1 = -2 cot?e 1- sec e 1+ sec e To establish the identity, start with the side containing the more complicated expression. Here, expressions on both sides are of the same complexity. Start with the expression on the left side. 1 Add the quotients. 1- sece 1+ sec 0 (1 + sec 0) + (1 – sec 0) (1 – sec 0)(1 + sec 0) (1- sec 0)(1 + sec 0) (1 + sec 0) + (1 – sec 0) (1 + sec 0) – (1 – sec 0) (1 - sec 0)(1 + sec 0) (1 - sec 0)(1+ sec 0) (1+ sec 0) – (1 – sec 0)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.2: Trigonometric Functions Of Angles
Problem 65E
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Question
Establish the following identity.
1
1
= -2 cot 20
1
- sec 0
1+ sec 0
.....
To establish the identity, start with the side containing the more complicated expression. Here, expressions on both sides are of the same complexity. Start with the expression on the left side.
1
1
+
Add the quotients.
%3D
1- sec 0
1+ sec 0
(1+ sec 0) + (1— sec Ө)
(1- sec 0)(1+ sec 0)
(1 - sec 0)(1 + sec 0)
(1+ sec 0) + (1 - sec 0)
(1 + sec 0) — (1 — sec Ө)
(1 - sec 0)(1 + sec 0)
(1 - sec 0)(1 + sec 0)
(1 + sec 0) - (1 – sec 0)
Transcribed Image Text:Establish the following identity. 1 1 = -2 cot 20 1 - sec 0 1+ sec 0 ..... To establish the identity, start with the side containing the more complicated expression. Here, expressions on both sides are of the same complexity. Start with the expression on the left side. 1 1 + Add the quotients. %3D 1- sec 0 1+ sec 0 (1+ sec 0) + (1— sec Ө) (1- sec 0)(1+ sec 0) (1 - sec 0)(1 + sec 0) (1+ sec 0) + (1 - sec 0) (1 + sec 0) — (1 — sec Ө) (1 - sec 0)(1 + sec 0) (1 - sec 0)(1 + sec 0) (1 + sec 0) - (1 – sec 0)
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