1- 2e+ e-25 F(s) 2

Q: ) Find the inverse Laplace transform, L-1{- 5 3 +e-2s s + 4. (s + 2

A: Find the inverse laplace transform using shifting theorem

Q: k divided by s2 + k2 is the inverse Laplace transform of,

A:

Q: Q1/ Find the laplace transform for the following 1 - e-6t sin(10t-8)

A:

Q: Find the inverse Laplace transform of Y(s) = (s-3)(s² +36) 2

A: Explanation of the answer is as follows

Q: Q2: find the laplace transform for the: y = e-*, x.cos2x

A:

Q: The Laplace transform of L(sin5t) is s2 + 25

A: We have to find the Laplace transform of sin5t

Q: find the inverse Laplace transform of the given function. 5.F(s)=2s−3s2−4

A: Given function is: Since the Laplace transform of: And

Q: Q1/ Find the laplace transform for the following 1 - e-6t.sin(10t-8)

A: By using properties of Laplace transform we solve the given problem as follows :

Q: What is the Laplace transform for the function: x(t) = 7te 8t +3. X(s) =

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Q: Question included in image

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Q: Find f(t) given that its Laplace transform is e-(s-2) F(s) = (s – 2)2 + 1

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Q: find the inverse Laplace transform of the given function. 1.F(s)=3s2+4

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Q: Q1/ Find the laplace transform for the following 2 - (t+2)?. cos 2t

A: We have to find Laplace transform of given function using Laplace transtorm Method.

Q: Find the inverse Laplace transform of 1 G(s) = s2 – 4s + 5

A: Given,

Q: Find the Laplace transform, F(s), of this function f(t) = e-2t t cos 3t

A: We use first shifting Theorem to find the Laplace transform of given function which states that  IF…

Q: L(e³t cos 2t)

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Q: Q3): Find the Laplace transform of ( choose only one ) : a- f(t)=5t-2 b- f(t)= (3 + e“ ) ?

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Q: L{t + e=2t}

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Q: find the Inverse LaPlace Transform, L ¯'{F(s)}. 32 L-1 + 4s. А. 4 — 2сost 8 – 8cos2t С. 8cos2t D. 1…

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Q: The Laplace transform of L(t + 5) is

A:

Q: The Laplace transform of L(t + 5)2et is

A: Here, we use first shifting theorem.

Q: Q3: Find the Laplace Transform L÷ (1- cos at)

A: Laplace transferom

Q: L{te¬3t cos 2t}

A:

Q: 6. Solve for the Laplace transform of f(t) = t^2 using the long method

A: Given that: f(t)=t2

Q: For x(t) shown below , the Laplace transform is

A:

Q: 1 s(s² +4)

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Q: Find the inverse Laplace transform of 3s + 2 F(s) 4s2 + 12s +9

A: We have to find the inverse Laplace transformation of…

Q: Use the definition of a Laplace Transform to find L[f(t)]. f (t) = e-5t

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Q: If f (t) = ) = CoS ( 4t what is 6 the laplace transform of f (t) ?

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Q: x(t) = (3 + e6t)²

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Q: f(t) = cos (2t)

A: To find the Laplace transform of the given function ft=cos22t

Q: L{e-2t cos 4t}.

A: Some Laplace transform formula: L{eatcosbt}=s-a(s-a)2+b2           (1) Given function is:…

Q: f(t) = 2Ct -4)

A:

Q: Solve for the laplace transform  x(t) = 3(t-5)5

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Q: The Laplace transform of L(t+ 5)2 is

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Q: Q1/ Find the Laplace transform of 1- f (t) = t² e cos 3t -2 x

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Q: )find the inverse Laplace transform 1 L-1 (p2 +1)2,

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Q: L cos2 t - t - and using the appropriate Laplace transform define 20. For (t) =

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Q: Find the Laplace transform, h(t) = H (t – 2m) cos 3 (t – 2m) s2+9

A: It is known that:  LHt-cft=e-csLft+cLcosat=ss2+a2

Q: Find the function f (t ) given its Laplace transform: 4 F( s ) = - 5s - 20

A: we know that if F(s)=L{f(t)}=1s-a then f(t)=L-1{F(s)}=eat and  L−1{aF(s)}=aL−1{F(s)}

Q: Find the Laplace transform of L{t^2cost}

A: Laplace transform of the form L(tkf(t))=(-1)kdkdskLf(t) Here, k=2, f(t)=cost From the identity,…

Q: Use the Laplace transform to solve the given problem: 3-5y = 0 dx

A: From table of Laplace table,

Q: Find the Laplace transform of f(t) = 31° - 8 cos 4t + e-24.

A: We will use the Laplace transform formulae to find the Laplace transform of the function f(t)

Q: Find the inverse Laplace transform, with respect to t, of s+2/s^2−4s+3

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Q: 1. x(t) = 3t5

A: Given Function: x(t)=3t5 constant multiplication property of Laplace Transform:…

Q: Find the inverse LaPlace transform F(s) = 2 4 35

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Q: 2 t+ 4t -5 e bE

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Q: Solve for the laplace transform using the formula. 9. F(t) = e-2t-

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Q: Find the Laplace transform of the function f(t) = (1+e2")² –- 1

A: Simplify the function.