-1 -2s [s²

Q: 2 Evaluate V2x +1

A:

Q: 6. Let [√16-X² Find y(2√3) 16-x? 2 16

A:

Q: 2 If C = |2 -1 0 Show that (C")-1 = (C-')" -2 2 2

A:

Q: )- ニ ZS+ト 32 |ニ2+

A: To solve the equation: x+y+z=12x-4y-3z=9-3x+2y+5z=-5

Q: Show that (k^2 * (k+1)^2)/(4) + (k+1)^3 is equal to ((k+1)(k+2)/2)^2

A:

Q: (п - 2)аn+1(2х — 3)п+1 + > ап-1 (2х — 3)"-1 n=0 n=2

A:

Q: 2. Let h(x) = |9 – x²].

A:

Q: 133. -Σ 2" Sn+ -(x + 2)" n=0

A: Consider the series, Rewrite this as Now take the constant outside,

Q: (-3 if z 2

A: Here is a step by step solution of the problem. We have proved discontinuity at x=2 by evaluation…

Q: -1 1 1 -1 -2 1 1 1 0 0 0 Given A = -5

A:

Q: A-1 does not exist.

A:

Q: P(Z -0.34) P(−0.25 <Z < -0.10)

A: (a)P(Z&lt; -1.12)=0.1313 From standard normal table,the graph is

Q: 2 3 0 1 4 0 0 1 2 A = 1

A:

Q: If f(2) =-3, g(2) =4, f' (2) =2- and g' (2) ==, then (2) - o' (2) =,

A:

Q: and conversely.

A:

Q: 1 1 0 2 1 1 B = |-1 2 1 1 0 0 1 2

A: We have the given matrix :  B=1102-12111012 First we have to find the basis for the col(B) . Next we…

Q: 5. = P - p2 Ans: = cet dt 1-P

A:

Q: then x-

A:

Q: -x if -3 sx S x if 0 sxs3 -x + 6 if 3 s IS6 21. f(x) = %3D

A:

Q: 0号 Inx= 3メ-23 2-2y 2) ③ -メ-+リーツ

A:

Q: 4х + Зу 3DIn(4х — Зу); у - 3y); ) || |

A:

Q: Зх —7%3D 8х + 23-

A:

Q: الواجُب (x-1) (x+4)<o 2 )و - رصه - (

A:

Q: (-1)**'n! 1-3-5..(2n+1) n+1

A: The objective is to find whether the series is convergent or divergent.

Q: -10 S- + 8$ +29 (28-35- 3) ?

A:

Q: 18%3D 0.5(6е - 12) 6e-12

A: Solve: 18=0.56e-12 And check f=18=0.56-12

Q: z(Z-7) at z= 5

A: =z(z-7)substitute z=5=55-7=5-2=-10

Q: (ь) (-6, 1/2) (r, 8) (r> 0) (r. 8) = (r< 0) y 2.0- -1.0 -0.5 0.5 1.0 1.5 1.0 -8 0.5- -10 -12- o-1.0…

A:

Q: diven that f(z) - S2-45 and g(z) - +2-9-9.

A:

Q: 2 1 1 1 0 1 2 4. A = | 0 1 1 , B = | 0 -1 [2 0 1

A:

Q: 1. Find r (-) and r (-)

A: We can answer first question as per the honor policy. Please resubmit the other question on by one…

Q: -1 -2 -3 -4- 1 2 Let A = 1 1-

A:

Q: j2 п(-1 + сos1) о )2 п(1+сos1) о ј2 п (1 - сos1) o j2ncos1

A:

Q: h(x) = e−3x;    h(1/4), h(2.5), h(−1), h(−?) h(1/4)= h(2.5)= h(-1)=

A:

Q: 12cos^2(t) + 2cos(t) - 2 =0 0≤t≤2π

A: Given that 12cos^2(t) + 2cos(t) - 2 =0 0≤t≤2π

Q: (*+7X-1) the f1) - -Sz+4) If fo- is undefined

A: Here first of all we find factors of denominator which is ( X - 1) ( X - 4)

Q: 5- 4- -5 -4 3 -2 -1 I| 2 3 4 5 -2 -3- -4 -5- Evaluate f( – 1) 3.

A:

Q: left of z=0.45

A: Given that  z=0.45 We need to find area left of z=0.45 In normal distribution graph it as follows.…

Q: (-5, 2). (3, -2) in z11 x Z4 is (0 ,5) (1 (3,0) (2 (3,5) None 4 3.

A: We have to find the element -5,2·3,-2 in Z11×Z4.

Q: Find Ai シ+ト+トz= \ + 0,5A-0-がアr ー /3

A: To find A1 and A2 from the given two equations

Q: -5 1 0 1 -6 1 0 1 0 -5 1 -6 0 5 2 0 A = 3 -1 0 6 -2 0 2 5

A:

Q: le 10- 5- 0- -5- -10- .... OC. OD. 10- 10-

A: We have to choose the correct answer from the given options according to the given information and…

Q: Z = X-p X-o / µ

A: P(Ac) = 1 - P(A)

Q: -3 4 (a) o 5 8 -5 (b) 0 4 -9 3 1. 7 -2 0 -8 -3 6 (c) 3 9. -3 7. (d) - - - r o0-

A: forming the linear equations from the matrix we have  x-3y+4z=7y+2z=2z=5 substituting the value of z…

Q: D = 2 O -1 -2 [0.5 0.5] 0.5 0.5 -2 -1 0 De₂ De 1 2 3 2 - -1 11 -2 -2 22 [0.866 -0.500] 0.500 0.866…

A:

Q: 2. 4s+32 s²-16

A: