i need the answer quickly 1²³-37²2² +27= 0 + 1 (1-1)(1-2) = 0.1₁=0, A2=1, d3 = 2X2XXY₁(x) = C₁ + c₂e² +₂²² +U₁=1, 4₂-e and U3=2²Yp = V₁ V₁ + U₂ V₂ + U3 V3 = V₁ + V₁₂ € + V₂ e²x2XVěU₁=0Ú₂ =ě M₂=22*2X₁F$A=0XGex 2x2e3xOZX2eйгÚ₂ =ě, Ú₂ = 42xe* 2xe 2²xŽ42XXe1+exوار3X3X.3X=(1) [4e²_2e²] =2²²-20XXe=-1/2=== *= -feed=== ਜਿੰਟਾHow did he get thevalue inside the circle

1-37+27= 0 ➜ 1 (1-1) (1-2)=0 1₁=0, A₂=1, d3=2 X 2X 21 Y₁₁(x) = C₁ + c₂e² +₂e² U₁1, U₁₂- and U₂=2² е 2X ур = U₁ V₁ + U₂ V₂ + Uz V3 = V₁ + V₁ € + √₂ 2²x e U₁=0 ₁ A=0 (ox 2X ex 2x e X G 2e3x 22 - کار - 42 - گار - 2 è X 2X X = Ž 42X X e 28x =(1) 2X 221+ex =1/1/2 X e 3X 3X [4e-2²²]=2²² 20 3X +v₁ = 1 + f +-feed X -ax tex 达V=1

1-37+27= 0 ➜ 1 (1-1) (1-2)=0 1₁=0, A₂=1, d3=2 X 2X 21 Y₁₁(x) = C₁ + c₂e² +₂e² U₁1, U₁₂- and U₂=2² е 2X ур = U₁ V₁ + U₂ V₂ + Uz V3 = V₁ + V₁ € + √₂ 2²x e U₁=0 ₁ A=0 (ox 2X ex 2x e X G 2e3x 22 - کار - 42 - گار - 2 è X 2X X = Ž 42X X e 28x =(1) 2X 221+ex =1/1/2 X e 3X 3X [4e-2²²]=2²² 20 3X +v₁ = 1 + f +-feed X -ax tex 达V=1

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter9: Systems Of Equations And Inequalities

Section9.7: The Inverse Of A Matrix

Problem 31E

See similar textbooks