Question
Asked Oct 20, 2019
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Use polar coordinates to find the limit. [Hint: Let x = r cos(θ) and y = r sin(θ), and note that (x, y) → (0, 0) implies r → 0.]

1 cos 2)
4 x2+ 42
lm
zy)-(0,0)
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1 cos 2) 4 x2+ 42 lm zy)-(0,0)

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Step 1

Given information:

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1-cos(x2+y2) The given expression is lim (xy)0,0) 4x24 +4y2

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Step 2

Simplify the expressi...

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1-cos(2cos2 0+r? sin20) lim 1-cosx lim (x0,0) 4x24y 4r2 cos2 04r2sin20 1-cos(rcos2 0+ sin2 lim 4r2(cos2 0+sin20' cos((1) 4r2(1) lim r0 cos(2 1- cos lim r0 472

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Tagged in

Math

Calculus

Limits