1/ Find the area of the region enclosed between the curves y= 2x²+10 and y=4x+16 and ,x=-2 and x-5? ans/ 142/3

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Q: 2. Find the area bounded by the two curves y = x² - 6x²+ 8x and y = x² - 4x.

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Q: 1/ Find the area of the region enclosed between the curves y= 2x+10 and y=4x+16 and ,x=-2 and x-5?…

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Q: 1/ Find the area of the region enclosed between the curves y= 2r²+10 and y=4x+16 and ,x=-2 and x-5?…

A: Given          y=2x2+10    and  y= 4x+16,   x=-2 and   x=5.

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Q: FInd the area bounded by the give curves y=6x2-8x-2 and y= 3x2+4x-11

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Q: 1/ Find the area of the region enclosed between the curves y= 2x2+10 and y=4x+16 and ,x=-2 and x=5?…

A: As per our guidelines we are supposed to answer only one question. Kindly repost other question as…

Q: problem in photo attached

A: Given,

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Q: Find the area between the curves: y=x^3-11x^2+18x and y = -x^3+11x^2-18x

A: y=x3-11x2+18x and y=-x3+11x2-18xTo find the area between the curves:

Q: Find the area of the region bounded by the curves y = -x² – 3x + 4 and y = x2 – 3x – 4.

A: We first sketch the region using a graphing calculator y=-x2-3x+4 (violet) y=x2-3x-4 (black)

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Q: 4. Find the area of the region bounded by the curves x-y² = 0 and x+2y² = 6.

A: Hence, the area of the region bounded by the curves x-y2=0 and x+2y2=6 is 82 square units .

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A: Given,      y= x2-2x-3and the x-axis  from  x=0 to x=6.

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Q: 2. Find the area of the region bounded by the graphs of y = x2 – 6 and y – 3 = 0. - -

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Q: 6. Find the area bounded by the curves of y = 6x + x² andy = -x² - 2x, and the linex = 5.

A: The equation of the curves are  C1: y = 6x+x2C2: y = -x2-2xC3: x = 5 To evaluate: The area of the…

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Q: Find the area under the curve 4x2-3x+6 between x= -2 and x=3

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Q: Find the area of the region between the curve y = √2x — 1 and the lines x = 1 and x = 5.

A: Given: The region between curve y=2x-1 and lines x=1 and x=5

Q: find the area of the region bounded by the curve y=x2 - 4x+3  , x axis and the lines x=2 and x=4

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Q: Find the area bounded by the curves y=x4-2x2 and y=-x2+4 at an [-1, 1].

A: The region bounded by the curves y=x4-2x2, y=-x2+4 in [-1,1] is:

Q: 1/ Find the area of the region enclosed between the curves y= 2x+10 and y=4x+16 and,x=-2 and x-5?…

A: We use integral to find area bounded by curve and lines

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.