Please help me with these statements.there are true / false statements.Thanks 1 If an event A is certain, then p(A) = 1.%3D2 If p(A) = 0.2, p(B) = 0.3, and p(AnB) = 0.1,then p(AUB) = 0.43 If the odds against A are 2:3, the probability of A is60%.4 If A = {set of all prime numbers less than 10} andB = {set of all numbers divisible by 2}, then theintersection of A and B contains two elements.5 An event and its complement are mutually exclusive.

Note: As per Bartleby guidelines, only 3 sub parts of a question can be solved at a time. so kindly…

Answered: 1 If an event A is certain, then p(A) =…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.8: Probability

Problem 35E

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Dividing a Jackpot A game between two pIayers consists of tossing coin. Player A gets a point if the coin shows heads, and player B gets a point if it shows tails. The first player to get six points wins an $8000 jackpot. As it happens, the police raid the place when player A has five points and B has three points. After everyone has calmed down, how should the jackpot be divided between the two players? In other words, what is the probability of A winning (and that of B winning) if the game were to continue? The French mathematicians Pascal and Fermat corresponded about this problem, and both came to the same correct conclusion (though by very different reasoning's). Their friend Roberval disagreed with both of them. He argued that player A has probability of Winning, because the game can end in the four ways H, TH, TTH, TTT, and in three of these, A wins. Roberval’s reasoning was wrong. Continue the game from the point at which it was interrupted, using either a coin or a modeling program. Perform this experiment 80 or more times, and estimate the probability that player A wins. Calculate the probability that player A wins. Compare with your estimate from part (a).

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1 If an event A is certain, then p(A) = 1. 2 If p(A) = 0.2, p(B) = 0.3, and p(AnB) = 0.1, then p(AU B) = 0.4 3 If the odds against A are 2:3, the probability of A is 60%.