1 kg is released from height h, = 12 m. Its path is withor 1) In Figure, a block with mass m = friction until it reaches the path with first length d,=2 m, where the friction force between B a C is f. = 8 N, and until it reaches the path, where the friction force between E and F is f, = 6 The height is h, = 1 m, and second horizontal length is d, = 1 m. The block continues its motio after the point F. (a) Find the velocity at the point A. (b) Find the velocity at the point D. (c) Find the height h if the velocity of m is vp= 8 m/s at the point F.(sin60=0.86 g=9.8 m/s?)
1 kg is released from height h, = 12 m. Its path is withor 1) In Figure, a block with mass m = friction until it reaches the path with first length d,=2 m, where the friction force between B a C is f. = 8 N, and until it reaches the path, where the friction force between E and F is f, = 6 The height is h, = 1 m, and second horizontal length is d, = 1 m. The block continues its motio after the point F. (a) Find the velocity at the point A. (b) Find the velocity at the point D. (c) Find the height h if the velocity of m is vp= 8 m/s at the point F.(sin60=0.86 g=9.8 m/s?)
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Transcribed Image Text:1) In Figure, a block with mass m = 1 kg is released from height h,
friction until it reaches the path with first length d,= 2 m, where the friction force between B and
C is f = 8 N, and until it reaches the path, where the friction force between E and F is f, = 6 N
The height is h, = 1 m, and second horizontal length is d, = 1 m. The block continues its motior
after the point F.
(a) Find the velocity at the point A.
(b) Find the velocity at the point D.
(c) Find the height h if the velocity of m is vp= 8 m/s at the point F.(sin60=0.86 g=9.8 m/s²)
12 m. Its path is withour
m
d,=1 m
h, = 12 m
D
60°
%3D
E
d;=2 m
h,=1 m
А В
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