1 Solve for x, x4 7 + 8 = 0 x2

Q: Solve for x. R Q (4.x+6)

A: given,

Q: U 10. Solve for x 171 ° -4 +23.x 9x + 6

A: Explanation: Given that,    Concept Used: Here we will use the Angles of intersecting chords…

Q: Solve for the unknown. In(x4) - In(x2) = 2

A:

Q: 2. Solve for X. (9x + 17) A (3х - 4)" (6х - 31)° B

A:

Q: 13. Solve for x: 5 + 4x - 2 23

A: Simplify the expression to make a single term of both sides of the equation. 4x-2=23-54x-2=18

Q: Solve for x. 17) 24x +3 26 -3

A: Verticle opposite angles are same

Q: 16. Solve for x: 34 - x = 3

A:

Q: 9 Solve for x in terms of b and c. 2x-b3Dc

A: Given  2x-b=c Add +b to the given equation on both sides

Q: 40 By using standard result solve E(2r -1) r=11

A: Given, ∑r=11402r-12 We have to solve it.

Q: 2. Solve for x: (a) -3.x* +2=0 4x3 +5x3 – 6=0 4x +5x -6=0 (d)

A:

Q: 4. Solve for x. * 23' (14x – 22)

A:

Q: 12. Solve for x using any method. |2x| >x - 5

A:

Q: 14. Solve for x. 2¯¾ = 8(x-3)

A: Given, 2-x2=8x-3

Q: 5. Solve for x. a. 10(6x-12) - 1 .

A:

Q: 34x - 12y = z solve for x

A: Topic = Algebra

Q: 2. Solve for x. 42 to

A: I am answering first question.

Q: Solve for x in simplest form. 2 15 = (4x + 9) 3

A:

Q: 4) Solve for x. * 5x+25 3x+4 3x-1- Your answer

A:

Q: 6.) Solve for x. V5 2.

A: Given triangle is :   To find the value of x

Q: 6. If QT =4x + 10 and QS = 17x- 43, solve for x. x3D

A:

Q: 9. Solve for x. (13x – 1)*

A: Part (9):- Given that

Q: 9. Solve for x: -1.2x = -9.6

A: Given-              -1.2x= -9.6

Q: 2. Solve for x, algebraically: -(x+ 5)(2x – 1)(x+ 2)

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: 10. Solve for x. A (8x-27)5 C (3x + 58)

A:

Q: 11. Solve for x. A, 92 (7x-10) 162

A:

Q: 28) Solve the equation for x: Vx + 5 = v2x - 5

A:

Q: 1 for x. 2 Solve - x+1 -+ 5 =

A: The given equation is                                               2x+1+5=1x

Q: 12) Solve for x: /8r - 2= V5x + 10

A:

Q: 4) Solve for x. Verify that your solution is correct using substitution. – 12) + 3x = 24

A: The objective of the question is solve the given equation and verify .

Q: O Solve x n+3 +X n+2 +7x n= 0

A:

Q: Solve for x. 5. 6ro 25° (5x+1)

A:

Q: 13. Solve for x. (11x-5)° (4x +29)° 679 (9x-15) 61 (6x + 13)°

A:

Q: X-1 Solve for x: x+3

A: Given: x-1x+3>0

Q: 7. Solve for x. P(2x + 6)° (3x+ 14)°

A:

Q: 8. Solve for x. (3r+ 27) (8r-12)

A:

Q: 2. Solve for x: (6x+26)° (16x) 5. Find m21. (12r +14)° (15x-13)°

A: This question related to angles when two parallel lines cut by transversal.

Q: Solve for x 2 1792 -X+ 66,05x¯+- 25 3613 3 5x=0 25

A: I am going to solve the problem by using some simple calculus to get the required result of the…

Q: C. 21) Solve for x. 3 X -2 8 + X

A: From the similar triangles ∆ABC and ∆ADE where DE∥BC, so ADAB=AEAC=DEBC            ...(1)

Q: 7. Solve for x: {x: xER, x<1}N{x: xER, x20}

A: Given

Q: 4) Solve for x. 5x+25 3x+4 3x-1- Your answer

A:

Q: 1. Solve for x: 35 – 12e-4* = 0

A: x = 5/4 - (1/4)ln(35/12)

Q: II. Solve for the indicated variable. x2 5x+7 2 X-1 + 4 a. for x 2-x 4 3

A:

Q: 7. Solve for x. 9х- 25 M 5x + 7 N

A:

Q: 1. Solve for x. 9x-43 3r+ 29

A: Opposite sides of a parallelogram are equal.

Q: 14. Solve for x. 3r + 1 10 7x-1 22

A: It is clear from the above diagram that both the triangles are similar to each other.  1st side of…

Q: 4. Solve for x. mx² + p- 2 = 5x

A:

Q: 2. Solve for x: 2 In(3x² +1)–13 = 0

A:

Q: 2. Solve for x. (x-3)3 - 16 = 0

A: Given, (x-3)23-16=0

Q: Solve the equation  In(X^2 +5x + 5)=0  for x

A: