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1 Table 2 4.7k E₁ lov Im 22kr Eronly s E Ency Its En only I' E & En-both active 10k Ry R5 Source TRy Computed IRY measured using! -220.6148 E₁ only I' = 403.34A Er only t E & EC-IL"= Ez IA 182.72741 Table 3 measured sources PRy umputed (P= IRy Ry using multisim E only - Er R₁ =4.7km kis 6.8kr R3 2 lok Ry= 22k-2 R5= 334-2 E₁ = lov E₁-15v

1 Table 2 4.7k E₁ lov Im 22kr Eronly s E Ency Its En only I' E & En-both active 10k Ry R5 Source TRy Computed IRY measured using! -220.6148 E₁ only I' = 403.34A Er only t E & EC-IL"= Ez IA 182.72741 Table 3 measured sources PRy umputed (P= IRy Ry using multisim E only - Er R₁ =4.7km kis 6.8kr R3 2 lok Ry= 22k-2 R5= 334-2 E₁ = lov E₁-15v

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Kindly help me solve this problem using Superposition Theorem and complete the tables given. Please show full and clean solution and also the circuit, thank you.

P= 7. Power is not a linear function as it is proportional to the square of either voltage or current. Consequently, Superposition Theorem should not yield an accurate result when applied directly to power. Based on the measured currents in Table 2, calculate the power in R4 using El-only and E2-only and record the values in Table 3. Adding these two powers yields the power as predicted by Superposition Theorem. Determine this value and record it in Table 3. The true power in R4 may be determined from the total measured current flowing through it. Using the experimental current measured when both E1 and E2 were active (Table 2), determine the power in R4 and record it in Table 3. IR R4 use measured I Source 1² + 1" measured El only E2 only " E1 + E2 1 E1 and E2 activa Table 3 computed PR4
Transcribed Image Text:P= 7. Power is not a linear function as it is proportional to the square of either voltage or current. Consequently, Superposition Theorem should not yield an accurate result when applied directly to power. Based on the measured currents in Table 2, calculate the power in R4 using El-only and E2-only and record the values in Table 3. Adding these two powers yields the power as predicted by Superposition Theorem. Determine this value and record it in Table 3. The true power in R4 may be determined from the total measured current flowing through it. Using the experimental current measured when both E1 and E2 were active (Table 2), determine the power in R4 and record it in Table 3. IR R4 use measured I Source 1² + 1" measured El only E2 only " E1 + E2 1 E1 and E2 activa Table 3 computed PR4
1 Table 2 4.7k E₁ lov Булчки Ry 10k Eronly s EEE IS En only I' E & En-both active R5 33452 Source TRy Computed IRY measured using! -220.6148 E₁ only I' = 403.34A Er only t E & EC-IL"s= Ez IA 182.72741 Table 3 measured sources PRy umputed P= IRy Ry using multisim E only - Er 15v R₁ =4.7km kis 6.8kr R3 lok R4=22k-2 2 R5= 33k-2 E₁ - Lov E₁-15V
Transcribed Image Text:1 Table 2 4.7k E₁ lov Булчки Ry 10k Eronly s EEE IS En only I' E & En-both active R5 33452 Source TRy Computed IRY measured using! -220.6148 E₁ only I' = 403.34A Er only t E & EC-IL"s= Ez IA 182.72741 Table 3 measured sources PRy umputed P= IRy Ry using multisim E only - Er 15v R₁ =4.7km kis 6.8kr R3 lok R4=22k-2 2 R5= 33k-2 E₁ - Lov E₁-15V
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