1 The region D above lies between the graphs of y = - 4 - (x + 1) and y = - 8 + (z + 3)*. It It can be describe in two ways. 1. If we visualize the region having "top" and "bottom" boundaries, express each as functions of x and provide the interval of r-values that covers the entire region. "top" boundary g2(x) = "bottom" boundary g1(x) = interval of æ values that covers the region = 2. If we visualize the region having "right" and "left" boundaries, then the "right" boundary must be defined piece-wise. Express each as functions of y for the provided intervals of y-values that covers the entire region. For – 5 < y < – 4 the "right" boundary as a piece-wise function f2(y) = For - 8 < y < - 5 the "right" boundary f2(y) =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 15T
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1
The region D above lies between the graphs of y = - 4 - (x + 1) and y =
- 8 +
(x + 3)*. It
9
can be describe in two ways.
1. If we visualize the region having "top" and "bottom" boundaries, express each as functions of x and
provide the interval of x-values that covers the entire region.
"top" boundary 92(x) =
"bottom" boundary g1(x) =
interval of x values that covers the region =
2. If we visualize the region having "right" and "left" boundaries, then the "right" boundary must be
defined piece-wise. Express each as functions of y for the provided intervals of y-values that covers the
entire region.
For – 5 < y < – 4 the "right" boundary as a piece-wise function f2(y) =
For – 8 < y < - 5 the "right" boundary f2(y) =
For –8 < y < - 4 the "left" boundary f1(y)
%3D
Transcribed Image Text:1 The region D above lies between the graphs of y = - 4 - (x + 1) and y = - 8 + (x + 3)*. It 9 can be describe in two ways. 1. If we visualize the region having "top" and "bottom" boundaries, express each as functions of x and provide the interval of x-values that covers the entire region. "top" boundary 92(x) = "bottom" boundary g1(x) = interval of x values that covers the region = 2. If we visualize the region having "right" and "left" boundaries, then the "right" boundary must be defined piece-wise. Express each as functions of y for the provided intervals of y-values that covers the entire region. For – 5 < y < – 4 the "right" boundary as a piece-wise function f2(y) = For – 8 < y < - 5 the "right" boundary f2(y) = For –8 < y < - 4 the "left" boundary f1(y) %3D
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