Solve in detail (1) The solution of the inequality 2 1 is(a) (-0, 1) U (3, +o0)(b) [1, 3](c) (1, 3)(d) (1, 3](2) The equation of the tangent line to the graph of f(r) = r² +1 at z = 1 is(a) y = 2r(b) y = 2r – 1(c) y = 3r – 1(d) y = 3r +1(3) The instantaneous rate of change of f(z) = r* at z = -2 is(a) -12(b) -12(c) -6(d) -8

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(1) The solution of the inequality 21 is (a) (-x, 1) U (3, +o0) (b) [1,3] (c) (1,3) (d) (1, 3] (2) The equation of the tangent line to the graph of f(x) = r +1 at z = 1 is (a) y = 2r (b) y = 2r – 1 (c) u= 3r -1

(1) The solution of the inequality 21 is (a) (-x, 1) U (3, +o0) (b) [1,3] (c) (1,3) (d) (1, 3] (2) The equation of the tangent line to the graph of f(x) = r +1 at z = 1 is (a) y = 2r (b) y = 2r – 1 (c) u= 3r -1

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Solve in detail

(1) The solution of the inequality 2 1 is
(a) (-0, 1) U (3, +o0)
(b) [1, 3]
(c) (1, 3)
(d) (1, 3]
(2) The equation of the tangent line to the graph of f(r) = r² +1 at z = 1 is
(a) y = 2r
(b) y = 2r – 1
(c) y = 3r – 1
(d) y = 3r +1
(3) The instantaneous rate of change of f(z) = r* at z = -2 is
(a) -12
(b) -12
(c) -6
(d) -8

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