1- The work done by the force F 41-31+2 k to displace a body from point (3,2,-1) to point (2,-1,4) is: a: 19 b:- (i+3j-5k) e:-4i+ 9j+ 10k d: 15

International Edition---engineering Mechanics: Statics, 4th Edition
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Author:Andrew Pytel And Jaan Kiusalaas
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Chapter6: Beams And Cables
Section: Chapter Questions
Problem 6.18P: For the ladder in Prob. 6.17, find the internal force system acting on section 2, assuming that x <...
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- The work done by the force F = 4 i- 3j + 2 k to displace a body from point (3,2,-1)
to point (2,-1,4) is:
e: -4i+ 9j+ 10k
2- A = i+ j, B= i - k and C = i +j-k, the scalar triple product is equal to:
a: 19
b: - (i+3j-5k)
d: 15
a: -1
b:-i
d: i
3- The projection of the vector i + 3 j +7k on the vector 21 + 6j + 3k is:
41
a 41
41
d: 4
4- If p = y? + xz , then curl grad o is equal to:
a: - 2j
b: 2f
2
d: zero
5- We can obtain the concept of impulse when the force is depend on:
a: velocity
6- If the acceleration a=2x and v= 0 when x=1 then the velocity as a function of x is:
a: [2(x? – 1)]1/2
b: time
c: distance
d: momentum
b: VZ x
e: 2(x - 1)
d: v2x
7- The acceleration vector in plan polar coordinates is a = (#- ré?)e, + (re + 2ré)ea,
if the particle moves in fixed radial line, then the radial and transverse components of
the acceleration are:
a rê? and rë
b:, f and 0
e: # and 2ré
d: 0 and rö
Transcribed Image Text:- The work done by the force F = 4 i- 3j + 2 k to displace a body from point (3,2,-1) to point (2,-1,4) is: e: -4i+ 9j+ 10k 2- A = i+ j, B= i - k and C = i +j-k, the scalar triple product is equal to: a: 19 b: - (i+3j-5k) d: 15 a: -1 b:-i d: i 3- The projection of the vector i + 3 j +7k on the vector 21 + 6j + 3k is: 41 a 41 41 d: 4 4- If p = y? + xz , then curl grad o is equal to: a: - 2j b: 2f 2 d: zero 5- We can obtain the concept of impulse when the force is depend on: a: velocity 6- If the acceleration a=2x and v= 0 when x=1 then the velocity as a function of x is: a: [2(x? – 1)]1/2 b: time c: distance d: momentum b: VZ x e: 2(x - 1) d: v2x 7- The acceleration vector in plan polar coordinates is a = (#- ré?)e, + (re + 2ré)ea, if the particle moves in fixed radial line, then the radial and transverse components of the acceleration are: a rê? and rë b:, f and 0 e: # and 2ré d: 0 and rö
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